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olga_2 [115]
4 years ago
6

Why do we change a^2-b^2 into (a + b)(a - b)?

Mathematics
1 answer:
sladkih [1.3K]4 years ago
5 0
You do this so that you can find the factors of the original equation of a^2 - b^2
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Please help asap!!! i’ll rate you most brainliest
SSSSS [86.1K]
I’m pretty sure it’s D??? But it also could be B I’m sorry :( trying to help as much as possible
6 0
3 years ago
When Janelle woke up, it was –3 degrees Fahrenheit outside. As the morning progressed, the temperature rose 2 degrees every hour
m_a_m_a [10]

Answer: g(x)

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
3. Given ABCD ≅ FGHJ and mC = 9x - 7, mH = 5x + 13, find the value of x and the measures of angle C and angle H. Show all work
Bas_tet [7]
Since congruence and similarity for polygons is posted in a specific order, we know that angle A=angle F, side A=side F, die B=side G, and so on. Therefore, we have that angle C=angle H = 9x-7=5x+13. Subtracting 5x from both sides to separate the x using the subtraction property of equality, we get 4x-7=13. Next, we can add 7 to both sides to get 4x=20, and divide both sides by 4 to isolate the x and get x=5. Plugging that into angle C or angle H, we get that 9x-7=9*5-7=45-7=38=5*5+13.

Feel free to ask further questions!
5 0
3 years ago
Which sum or difference identity would you use to verify that cos (180° - q) = -cos q?
Phantasy [73]

Answer:

\cos (a-b)=\cos a \cos b+\sin a \sin b

Step-by-step explanation:

 Given : \cos (180^{\circ}-q)=-\cos q

We have to write which identity we will use to prove the given statement.

Consider \cos (180^{\circ}-q)=-\cos q

Take left hand side of given expression \cos (180^{\circ}-q)

We know

\cos (a-b)=\cos a \cos b+\sin a \sin b

Comparing , we get, a= 180° and b = q

Substitute , we get,

\cos (180^{\circ}-q)=\cos 180^{\circ}  \cos (q)+\sin q \sin 180^{\circ}

Also, we know \sin 180^{\circ}=0 and \cos 180^{\circ}=-1

Substitute, we get,

\cos (180^{\circ}-q)=-1\cdot \cos (q)+\sin q \cdot 0

Simplify , we get,

\cos (180^{\circ}-q)=-\cos (q)

Hence, use difference identity to  prove the given result.

7 0
4 years ago
Read 2 more answers
Vernon's work for finding the value of x is shown below. Lines A C and B D intersect at point E. Angle A E D is (16 x + 8) degre
Marta_Voda [28]

Answer:

<em>No, he should have set the sum of ∠AED and ∠DEC equal to 180°, rather then setting ∠AED and ∠DEC equal to each other</em>

Step-by-step explanation:

Find the diagram attached

If line AC and BD intersects, then m<AED + m<DEC = 180 (sum of angle on a straight line is 180 degrees)

Given

m<AED = 16x+8

m<DEC = 76 degrees

16x + 8 + 76 = 180

16x + 84 = 180

16x = 180-84

16x = 96

x = 96/16

x = 6

Hence the value of x is 6

Hence the correct option is <em>No, he should have set the sum of ∠AED and ∠DEC equal to 180°, rather then setting ∠AED and ∠DEC equal to each other</em>

5 0
3 years ago
Read 2 more answers
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