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Alisiya [41]
3 years ago
10

I will give Brainliest please help me.

Mathematics
1 answer:
dlinn [17]3 years ago
5 0
Hello,

To answer your problem, use the Pythagorean Theorem for 2 right triangles and the Area of a Rectangle to find the Area of the Parallelogram.

All together:

A = 2(area of right triangle) + (area of rectangle)

A = 2[1/2*b*h] + [b*h]

To find the area of the parallelogram, I would be here for a while. Haha

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Fynjy0 [20]

Answer:

i do not know

Step-by-step explanation:

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8 0
3 years ago
Name the Solid.
Andrew [12]

Answer:

41,223.98

Step-by-step explanation:

Find the volume of the full sphere, then divide by 2 to get 1/2 of a sphere.

The answer for the full sphere is 82447.96 but divide by 2 and get 41,223.98.

6 0
3 years ago
Read 2 more answers
One of u guys helped me but they keep returning it saying show your work>:(​
Rom4ik [11]

Answer:  She will need 36 yards of material.

Step-by-step explanation:

16 × 2¹/₄ can be done different ways,

First multiply ¹/₄ times 16. that is the same as dividing 16/4 = 4

Then multiply 2 times 16  2×16 = 32

Add 32 + 4 = 36

Another way is to change 2¹/₄ to an improper fraction and multiply

⁹/₄ × 16

   16

  <u> ×9</u>

   54  

<u> +9   </u>

 144

 

144/4 = 36

<u />

6 0
3 years ago
Read 2 more answers
6
ioda
$6.060606- because in this situation she has $10 and the rate is $1.65 with no additional rate or fee.
So you would need to do 10/1.65 and round it down to find the whole or keep the decimals to get an exact answer
Answer:6.060606
5 0
3 years ago
Let tk(x)tk(x): be the taylor polynomial of degree k of the function f(x)=sin(x)f(x)=sin⁡(x) at a=0a=0.suppose you approximate f
Aloiza [94]
<span>Ans : Note that: sin(x) = sum(n=0 to infinity) [(-1)^n * x^(2n + 1)]/(2n + 1)!. Then, since the series is alternating, the error in the approximation found by taking the first n terms of the series is no bigger than the n+1'th term. In other words: E ≤ a_n+1 = x^(2n + 3)/(2n + 3)!. (Note that a_n does not include (-1)^n, the alternating part) We need that 1/6 ≤ x^(2n + 3)/(2n + 3)!. Given |x| < 1, n = 2 will be the least integer solution. Thus, we need 2 + 1 = 3 terms.</span>
4 0
3 years ago
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