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n200080 [17]
2 years ago
9

James deposited $575 into a bank account that earned 5.5% simple interest each year. No money was deposited into or withdrawn fr

om the account. How much money was in the account after ​ ​ 2 1/2 ​ ​ years? Round your answer to the nearest cent.
Mathematics
2 answers:
sweet [91]2 years ago
6 0

Answer:

$654.06

Step-by-step explanation:

ジオメトリヘルプミープリーズは、速くて正しい場合に最も頭が良くなります

関係のドメインは? 1)関係の出力(y)値2)関係の入力(x)値3)入力値をペアにするポイントのセット…

f(x)= 16 – x ^ 2、g(x)= 4 –xとします。 (fg)(x)とその定義域を見つけます。

助けてくださいお願いします

助けてください

Aloiza [94]2 years ago
5 0

Answer: the answer would be 79.06

Step-by-step explanation:

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Trina uses 1/2 cup of sugar and 3/4 cup of flour in a recipe. How many cups of sugar would she need if she uses 3 cups of flour?
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First add 1/2 and 3/4 then add that answer by 3
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Answer:

I THINK C

Step-by-step explanation:

I THINK.

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Identify the ordered pair on the graph of the equation 2x + 5y = 4.
Colt1911 [192]
What you would do is you would substitute each ordered pair into their respective variables. (ie. for (0,1) you would put 0 where the x is and 1 where the y is) You would then solve the equation. If the equation is not even (ie. 2=5 would not be even but 4=4 would be), you move on to the next ordered pair.

If you follow the process right and you get the equations correct, the answer should be B. (7,-2)
6 0
2 years ago
The standard deviation of math test scores at one high school is 16.1. A teacher claims that the standard deviation of the girls
Elanso [62]

Answer:

\chi^2 =\frac{22-1}{259.21} 166.41 =13.482

p_v =P(\chi^2

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(13.482,21,TRUE)"

If we compare the p value and the significance level provided we see that p_v >\alpha so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population deviation is not significantly lower than 16.1 at 1% of significance.

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

n=22 represent the sample size

\alpha=0.01 represent the confidence level  

s^2 =12.9^2=166.41 represent the sample variance obtained

\sigma^2_0 =16.1^2 =259.21 represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population deviation is smaller than 16.1 (that's equivalent to check if the population variance is lower than 259.21:

Null Hypothesis: \sigma^2 \geq 259.21

Alternative hypothesis: \sigma^2

Calculate the statistic  

For this test we can use the following statistic:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

\chi^2 =\frac{22-1}{259.21} 166.41 =13.482

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case 21. And since is a left tailed test the p value would be given by:

p_v =P(\chi^2

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(13.482,21,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that p_v >\alpha so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population deviation is not significantly lower than 16.1 at 1% of significance.

3 0
3 years ago
The diameter of a sphere is 11.8m calculate the spheres volume
Iteru [2.4K]
The volume is 860.29m³
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3 years ago
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