It gives function: h = -16t^2 + 40
water is when height is 0 so solve for 0= -16t^2 + 40
subtract 40 from both sides: -40 = -16t^2
divide by -16: -40/-16 = t^2
simplify: 5/2 = t^2
square root both sides: 1.58 = t
the orange hits the river in 1.58 seconds.
Step-by-step explanation:
then poured into another container with a rectangular base of length 27 cm and width 11 cm. Calculate the depth (height) of the water in the rectangular container
Step-by-step explanation:
Steps of Construction
(i) Draw ray AB.
(ii) Construct ∠BAC = 60°.
(iii) Construct ∠BAD = 90°.
(iv) Bisect ∠CAD, so that ∠CAE = ∠EAD = 15°.
(v) We obtain ∠BAE = ∠BAC + ∠CAE = 60° + 15° =75°.
Hope this Helps!!!!
Answer:
the answer will be +4 each time