Answer:
Step-by-step explanation:
Given that a survey found that women's heights are normally distributed with mean 63.4 in and standard deviation 2.2 in.
Let X be the random variable representing women heights.
P(58<X<80)
Z for 58 = -2.454
Z for 80 = 7.545
P(-2.454<Z<7.545) = 0.4945+0.5=0.9945
-5(3+8x+3x^2) this was my answer I’m sorry if I’d gotten it wrong
Answer:
V=4298.0915\approx 4298.09
V=4298.0915≈4298.09
Step-by-step explanation:
Answer:
What problem?
Step-by-step explanation:
I dont see anything
Answer:
720.8
Step-by-step explanation:
(2.6 × 106) + (4.2 × 106)
275.6 + 445.2
720.8