We know that
speed=distance/time
solve for time
time=distance/speed
in this problem
<span>Marco runs at a rate of 6 miles per hour.
</span><span>Fernando funs at a rate of 7.2 miles per hour
Difference=7.2-6=1.2 miles/hour
so
speed=1.2 miles/hour
distance=0.3 miles
time=?
</span>time=distance/speed-----> 0.3/1.2-----> 0.25 hour-----> 0.25*60=15 minutes
<span>
the answer is
0.25 hour (15 minutes)
Alternative Method
Let
x---------> Fernando's distance when Marco is 0.3 miles apart
</span>Fernando funs at a rate of 7.2 miles per hour
<span>for distance =x
time=x/7.2------> equation 1
</span>Marco runs at a rate of 6 miles per hour.
for distance=x-0.30
time=(x-0.30)/6------> equation 2
equate equation 1 and equation 2
7.2*(x-0.3)=6x-----> 7.2x-2.16=6x
7.2x-6x=2.16------> x=2.16/1.2-------> x=1.8 miles
time=x/7.2-----1.8/7.2=0.25 hour
Move -4 to the other side
7x=24+4
7x=28
x=4
It should be (2x-3)x(3x+2)
Answer:
Horizontal distance = 1.98 m (Approx)
Step-by-step explanation:
Given:
Height = 2.5 m
Speed v = 2.8 m/s
Find:
Horizontal displacement
Computation:
s = ut + (1/2)gt²
2.5 = (1/2)(9.8)t²
t² = 0.5102
t = 0.7079 s
Horizontal distance = (v)(t)
Horizontal distance = (2.8)(0.7079)
Horizontal distance = 1.98 m (Approx)
Answer:
c)11√2
Step-by-step explanation:
Given that two of the angles are equal ,each measuring 45 degrees then two legs will be equal as well each measuring 11 units. We have a right angled triangle with two sides given and we are required to determine the hypotenuse. We use Pythagoras theorem;
hypotenuse^2 = 11^2 + 11^2
hypotenuse ^2 = 242
hypotenuse = 
hypotenuse = 
