Answer:
AMY
BMY
BMX
Step-by-step explanation:
I took the assignment
You need to use the identity
cos(90-u)=sin(u)
if u=x-20
cos(90-x+20)=sin(x-20)
cos(110-x)=sin(x-20)
substituting in the original function
cos(110-x)=cos(42)
for the functions to be equal there input must be equal
110-x=42
x=68
The easiest way would be to subtract 112 from 158 to get 46 that is the difference. Then divide by 2 to find the speed of wind, in this case that would be 23. So the wind speed was 23 km/h and to get the plane speed add or subtract 23 from the sped of the plane (112+23 or 158-23) to get 135 km/h so the plane moved at 135 km/h while the wind speed was 23 km/h
Answer:
1. cos(F) = 2. 5/13
tan (F) = 3. 12/5
sin (F) = 1. 12/13
2. Sin (R) = 1. 60/68 = 30/34 = 15/17
cos (R) = 2. 32/68 = 16/34 = 8/17
tan (R) = 3. 60/32 = 30/16 = 15/8
Step-by-step explanation:
1 picture:
sin = Opp/Hyp
cos = adj/hyp
tan = opp/adj
cos(F) = 2. 5/13
tan (F) = 3. 12/5
sin (F) = 1. 12/13
2 Picture:
Sin (R) = 1. 60/68 = 30/34 = 15/17
cos (R) = 2. 32/68 = 16/34 = 8/17
tan (R) = 3. 60/32 = 30/16 = 15/8