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3 years ago

Which point identifies the intersection of two lines with slopes that multiply to −1?

Mathematics

1 answer:

Sever21 [200]3 years ago

3 0

Answer:

Perpendicular lines are lines that intersect at right angles. If you multiply the slopes of two perpendicular lines in the plane, you get −1 . That is, the slopes of perpendicular lines are opposite reciprocals .

Hope this help:)

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A magazine has 120 pages. There are 28 full-page ads and 12 half-page ads. The rest of the magazine consists of articles.

Finger [1]

Answer:

120 = 28 + 12(½) + X

Where X is the no. of pages of articles

120 = 28 + 6 + X

X = 120 - 34

X = 86

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3 years ago

Read 2 more answers

Is f(x) continuous at x equals 4? Why or why not? A. No, f(x) is not continuous at x equals 4 because ModifyingBelow lim Wit

soldier1979 [14.2K]

Corrected Question

Is the function given by:

$f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right$

continuous at x=4? Why or why not? Choose the correct answer below.

Answer:

(D) Yes, f(x) is continuous at x = 4 because $Lim_{x \to 4}f(x)=f(4)$

Step-by-step explanation:

Given the function:

$f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right$

A function to be continuous at some value c in its domain if the following condition holds:

f(c) exists and is defined.

$Lim_{x \to c}$ f(x)$ exists.

$f(c)=Lim_{x \to c}$ f(x)$

At x=4

$f(4)=\dfrac{1}{4}*4+1=2$

$Lim_{x \to 4}f(x)=2$

Therefore: $Lim_{x \to 4}f(x)=f(4)=2$

By the above, the function satisfies the condition for continuity.

The correct option is D.

3 0

3 years ago

A rocket is launched into the air. The height h(t), in yards, of the rocket is a function of time, t, in seconds, as shown in th

Vesna [10]

Answer:

Step-by-step explanation:

Average rate of change is the same thing as the slope. Because this is parabolic, we cannot find the exact rate of change as we could if this were a linear function. But we can use the same idea. When t = 3, h(t) = 33, so the coordinate point is (3, 33). When t = 6, h(t) = 0, so the coordinate is (6, 0). Plug those values into the slope formula:

$m=\frac{0-33}{6-3}$ and