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cluponka [151]
3 years ago
7

6) A bag is full of different colored marbles. The probability of randomly selecting a red marble from

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
4 0

Answer:

The probability of drawing a red marble = 2/5. The probability of drawing a blue marble is now = 1/4.

Step-by-step explanation:

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HELPPP PLEASE!!! I’M BEING TIMED!!!!
Evgesh-ka [11]

Answer:

y= -7x -27

Step-by-step explanation:

5 0
3 years ago
Mr. Bridges paid $582.40 for a set of four tires for a truck about how much was the cost per tire
skelet666 [1.2K]
$582.40 / 4 tires = $145.60

Answer: $145.60/tile
5 0
3 years ago
what is the slope of the line that passes through the points (-4,-4) and (-4,-9)? Write your answer in simplest form
Aneli [31]

Answer:

undefined

Step-by-step explanation:

We can find the slope of a line using two points by

m = (y2-y1)/(x2-x1)

   = (-9- -4)/(-4 -  -4)

    = (-9+4)/(-4+4)

   = -5/0

When we divide by zero, our solutions is undefined

The slope is undefined

3 0
3 years ago
Reduce the fraction -20t5u2v3 / 48t7u4v .
kondor19780726 [428]
Deal with the numbers and variables step by step 

-20/48  = -5/12
t5 / t7 = t^-2 = 1 /t2
u^2 / u^4 = u^-2 = 1/u^2
v^3 / v = v^2

so answer is      -5v^2 / 12t^2u^2
6 0
4 years ago
Given f(x) =
sergejj [24]

Answer:

A

Step-by-step explanation:

We are given the function:

\displaystyle f(x) = \left\{        \begin{array}{ll}            2\cos(\pi x) \text{ for }  x \leq -1 \\ \\          \displaystyle   \frac{2}{\cos(\pi x)}\text{ for } x > -1        \end{array}    \right.

And we want to find:

\displaystyle \lim_{x\to -1}f(x)

So, we need to determine whether or not the limit exists. In other words, we will find the two one-sided limits.

Left-Hand Limit:

\displaystyle \lim_{x\to-1^-}f(x)

Since we are approaching from the left, we will use the first equation:

\displaystyle =\lim_{x\to -1^-}2\cos(\pi x)

By direct substitution:

=2\cos(\pi (-1))=2\cos(-\pi)=2(-1)=-2

Right-Hand Limit:

\displaystyle \lim_{x\to -1^+}f(x)

Since we are approaching from the right, we will use the second equation:

=\displaystyle \lim_{x\to -1^+}\frac{2}{\cos(\pi x)}

Direct substitution:

\displaystyle =\frac{2}{\cos(\pi (-1))}=\frac{2}{\cos(-\pi)}=\frac{2}{(-1)}=-2

So, we can see that:

\displaystyle \displaystyle \lim_{x\to-1^-}f(x)=\displaystyle \lim_{x\to -1^+}f(x) =-2

Since both the left- and right-hand limits exist and equal the same thing, we can conclude that:

\displaystyle \lim_{x \to -1}f(x)=-2

Our answer is A.

8 0
3 years ago
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