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Brilliant_brown [7]
2 years ago
11

Helppppp!!!! Ty ✨:)))))))))

Mathematics
2 answers:
LiRa [457]2 years ago
8 0

Answer:

12/7 or 1 5/7

Step-by-step explanation:

6 * 2 = 12

so

12/7 = 1 5/7

Varvara68 [4.7K]2 years ago
3 0

Answer:

1.714 and/or 1 5/7

Step-by-step explanation:

You're welcome :P

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aksik [14]

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I don't get the question very well

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12% of people are wearing sunglasses. If
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500 people?Not too sure but that is my best guess

Step-by-step explanation:

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Rasek [7]

Answer:

3/4 and 0.95 would both result in a reduction.

Step-by-step explanation:

multiplying by anything less than 1 will make it smaller which both 3/4 and 0.95 are smaller than 1.

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I have no idea what the answers are
lara [203]

Hello from MrBillDoesMath!

Answer:

Top line: y = (2/3)x + 2

Bottom line:  y = (2/3)x  -1

Discussion:

The graph provided is hard to read but I did the best I could.

The top line appears to pass through the points (0,2) and (-3,0)

For this line

m =  change y /change x = (0-2)/(-3-0) = -2/-3 = +2/3. So

y = mx + b => y = (2/3) x+ b.  As the line passes through (0,2) set x = 0, y= 2 in y = (2/3)x + b =>  

2 = (2/3) 0 + b   => b = 2

Therefore    y = (2/3)x + 2

The bottom line appears to pass through the points (0,-1) and (3,1)

For this line

m =  change y /change x = (1-(-1)) /(3-0) = +2/-3. So

y = mx + b => y = (2/3) x+ b.  As the line passes through (0,-1) set x = 0, y= -1  in y = (2/3)x + b =>  

-1  = (2/3) 0 + b   => b = -1

Therefore    y = (2/3)x + -1

Thank you,

MrB

5 0
3 years ago
GEOMETRY!!! 15 PTSSSSS
ss7ja [257]

Answer:

23) option c

    JL ≈ 9.3

25) option c

      y ≈ 9.6

Step-by-step explanation:

<h3>25)</h3>

Given in the question that,

cos(21°) = 9 / y

y = 9/cos(21°)

y = 9.64

y ≈ 9.6(nearest tenth)

<h3>23)</h3>

Given in the question that the hypotenuse of right angle triangle = 12

To find,

height of the right angle triangle

angle k = 39°

so by using trigonometry identity

cos(39) = opp/hypo

cos(39) = JL / KL

JL = cos(39)(12)

JL = 9.32

JL ≈ 9.3

<h3 />
4 0
3 years ago
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