Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

(1)
By Quadratic Formula:

,
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
40 miles per hour. if you take 60 divided by 1.5(the speed over time) you get 40mph
Answer:
114.5 in³
Step-by-step explanation:
Volume of cone:
⅓ × 3.14 × 8² × 12
= 803.84 cm³
Volume of hemisphere:
⅔ × 3.14 × 8³
= 1071.786667 cm³
Total = 803.84 + 1071.786667
= 1875.626667 cm³
1 cm = 0.393701 inches
1 cm³ = 0.393701³ inches
Volume in in³:
1875.786667/0.393701³
= 114.4579471 in³
The first one is 7.4 . 39/5=7 and 4 change so 7.4 . The second one is 1.67 . 5/3 is 1.6 repeated and rounded to the nearest houndredth is 1.67
9514 1404 393
Answer:
AD is the diameter
Step-by-step explanation:
Angles in a triangle have a sum of 180°, so inscribed angle B is 80° and inscribed angle E is 90°.
An inscribed angle subtends an arc that is twice its measure, so arcs ABD and AED are both 180°. That makes chord AD a diameter.
Points A and D need your cross markings. AD is a diameter of the circle.