Answer:
A(n) videoconference allows people at two or more locations to interact via two-way video and audio transmissions simultaneously as well as share documents, data, computer displays, and whiteboards.
Answer:
There is no need to make an algorithm for this simple problem. Just add the two numbers by storing in two different variables as follows:
Let a,b be two numbers.
c=a+b;
print(c);
But, if you want to find the sum of more numbers, you can use any loop like for, while or do-while as follows:
Let a be the variable where the input numbers are stored.
while(f==1)
{
printf(“Enter number”);
scanf(“Take number into the variable a”);
sum=sum+a;
printf(“Do you want to enter more numbers? 1 for yes, 0 for no”);
scanf(“Take the input into the variable f”);
}
print(Sum)
Explanation:
hi there answer is given mar me as brainliest
Answer:
false
Explanation:
i believe the right term is error
Answer:
import java.util.*;
public class Main {
public static void main(String[] args)
{
Scanner scan = new Scanner();
double budget=0, num=0, total=0;
System.out.println("Your budget for the month? ");
budget=scan.nextDouble();
System.out.println("enter all expense, and after that type -9999 to quit: ");
while(num != -9999)
{
total+=num;
num=scan.nextDouble();
}
if(total<=budget)
{
System.out.println("under budget by ");
System.out.println(budget-total);
}
else
{
System.out.println("over budget by ");
System.out.println(total-budget);
}
}
}
Explanation:
- Take the budget as an input from user and store it to the budget variable.
- Loop until user has entered all his expenses and keep on adding them to the total variable.
- Check If the total is less than or equal to budget or otherwise, and then print the relevant message accordingly.
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Hope this helps :)
