Answer:
a. dQ/dt = -kQ
b.
c. k = 0.178
d. Q = 1.063 mg
Step-by-step explanation:
a) Write a differential equation for the quantity Q of hydrocodone bitartrate in the body at time t, in hours, since the drug was fully absorbed.
Let Q be the quantity of drug left in the body.
Since the rate of decrease of the quantity of drug -dQ/dt is directly proportional to the quantity of drug left, Q then
-dQ/dt ∝ Q
-dQ/dt = kQ
dQ/dt = -kQ
This is the required differential equation.
b) Solve your differential equation, assuming that at the patient has just absorbed the full 9 mg dose of the drug.
with t = 0, Q(0) = 9 mg
dQ/dt = -kQ
separating the variables, we have
dQ/Q = -kdt
Integrating we have
∫dQ/Q = ∫-kdt
㏑Q = -kt + c
when t = 0, Q = 9
So,
c) Use the half-life to find the constant of proportionality k.
At half-life, Q = 9/2 = 4.5 mg and t = 3.9 hours
So,
taking natural logarithm of both sides, we have
d) How much of the 9 mg dose is still in the body after 12 hours?
Since k = 0.178,
when t = 12 hours,
Answer:
∠MON = 57°
Step-by-step explanation:
∠LOM + ∠MON = ∠LON ← substitute values
3x + 20 + 2x + 33 = 113, that is
5x + 53 = 113 ( subtract 53 from both sides )
5x = 60 ( divide both sides by 5 )
x = 12
Hence
∠MON = 2x + 33 = (2 × 12) + 33 = 24 + 33 = 57°
Answer:
Parameter
Step-by-step explanation:
Parameter and statistic:
- Parameter is a numerical value that describes a population.
- A sample is a part of the population and always smaller than the population.
- The statistic is a numerical value that describes a sample.
Population of interest:
College students aged 18 to 22
Parameter:
66.4% reported using alcohol within the past month
Thus, the given is a parameter as it describes a population proportion.
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You round and than write it like example if you have 763,678 what is the 60 thousand rounded up to than you will put 760,000 I hope I awnsered your question