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liubo4ka [24]
2 years ago
5

1 Candice is taking a group nature hike in a park. There is a $13.00 fee just to enter the park. In addition, the tour group cha

rges $0.24 per mile they hike. She brought $64.00 with her. Which equation can be used to determine how many miles can she hike? ​
Mathematics
1 answer:
d1i1m1o1n [39]2 years ago
7 0

Answer:

There is a $12.00 fee just to enter the park. ... In addition, the tour group charges $0.23 per mile they hike. She brought $35.00 with her. Which equation can be used to determine how many miles can she hike? ... 1. Brainly User. Let, the miles she can travel = d. So, Equation would be: 12.00 + 0.23d = 35.00

Step-by-step explanation:

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186000km in 6 hours

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Simplify: (-5a³-7a² +3)+(-9a³ +5a² +9)​
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Answer: =−14a3−2a2+12

Step-by-step explanation:

−5a3−7a2+3−9a3+5a2+9

=−5a3+−7a2+3+−9a3+5a2+9

Combine Like Terms:

=−5a3+−7a2+3+−9a3+5a2+9

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Answer:

=−14a3−2a2+12

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2 years ago
The coffee beans from 14 trees are required to produce 7.7 kg of coffee. This is the
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34,496

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5 0
3 years ago
A point in the figure is selected at random find the probability that a point will be in the part that is not selected
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6 0
3 years ago
The data given to the right includes data from ​candies, and of them are red. The company that makes the candy claims that ​% of
Dafna1 [17]

Using the z-distribution, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

Researching this problem on the internet, 8 out of 39 candies are red, hence the sample size and the estimate are given by:

n = 39, \pi = \frac{8}{39} = 0.2051

Hence the bounds of the interval are:

  • \pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2051 - 1.96\sqrt{\frac{0.2051(0.7949)}{39}} = 0.0784
  • \pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2051 + 1.96\sqrt{\frac{0.2051(0.7949)}{39}} = 0.3318

As a percentage, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

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2 years ago
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