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Blababa [14]
3 years ago
10

Substituting x= -3 in x2 + 5x +4 gives?​

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
6 0

Answer:

-2

Step-by-step explanation:

If we replace all the spots where x is with -3, we get this: (-3)^2 + 5(-3) + 4. Then we get... 9 + -15 + 4 which equals -2

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A family spends 1/3 of its income for the mortgage and 1/6 of its income for food. What proportion of its income remains?
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Answer: 1/2

Step-by-step explanation:

1/3 = 2/6 so 2/6 + 1/6 = 3/6

3/6 = 1/2

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The Roman numeral which represents the number in standard form for 3,089 is?
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What is 2x+8y=12 in slope intercept form <br>as well as x-2y=0 in slope intercept form 
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the \ slope \ intercept \ form \ is : \\ \\ y= mx +b \\ \\ 2x+8y=12 \ \ |-2x \\ \\8y=-2x+12\ \ /:8\\ \\y=-\frac{2}{8}x+\frac{12}{8}

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8 0
3 years ago
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The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of
SCORPION-xisa [38]

Answer:

a) 51.60% probability that in a given year there will be less than 21 earthquakes.

b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 4.5

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.8}{4.5}

Z = 0.04

Z = 0.04 has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 20.8}{4.5}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 20.8}{4.5}

Z = -0.62

Z = -0.62 has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

5 0
3 years ago
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