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3 years ago

PLEASE ANSWER FAST

Biology

2 answers:

olasank [31]3 years ago

4 0

Answer:

D. Sensory Neuron

Explanation:

Sensory neurons are the nerve cells that are activated by sensory input from the environment.

Juliette [100K]3 years ago

3 0

Answer:

D. sensory neurone

Explanation:

sensory neurone receives information via their receptors, which are part of the peripheral nervous system, and convert this information into electrical impulses.

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Explain the difference between the zone of aeration and the zone of saturation.

KiRa [710]

Answer:

The soil and rocks in the zone of aeration have pores which are partially filled with water and air. The zone of saturation comprises rocks and soil whose pores are saturated with water. 3. The zone of saturation lies beneath the water table, while the zone of aeration lies above it.

Explanation:

8 0

3 years ago

The bones from an animal found at an archaeological dig have a C614 activity of 0.10 Bq per gram of carbon. The half-life of C61

erastova [34]

C14 is an isotope used in radiocarbon dating techniques to date organic matter remains. The age of these bones is approximately 6890 years.

<h3>What is Carbon 14?</h3>

Carbon 14, also known as radiocarbon, is a radioactive carbon isotope.

Isotopes are the atoms of the same element -carbon- that vary in neutrons and, hence, in their massic number. They are alternative forms of the same element.

The radioactive C14 nucleus contains 6 protons and 8 neutrons and has a half-life of 5730 years.

The term half-life is a reference. It means that an organism that has been dead for 5730 years has half the C14 amount or concentration than the same organism had when it was alive.

Knowing the half-life of an element is useful to determine the age of the dead matter.

C14 is used in radiocarbon dating techniques or methods to estimate the age of fossils. This is a reliable technique used for dating organic samples that are less than 50,000 years old.

Available data:

The half-life of C14 is 5730 years
Bones activity of 0.10 Bq per gram of carbon

To answer this question we can make use of the following equation

Ln (C14T₁/C14 T₀) = - λ T₁

Where,

C14 T₀ ⇒ Amount of carbon in a living body. We know, by bibliography, that living organism activity is 0.23 Bq per gram of carbon. So, C14 T₀ = 0.23 Bq/g

C14T₁ ⇒ Amount of carbon in the dead body. C14T₁ = 0.1 Bq/g

λ ⇒ radioactive decay constant = (Ln2)/T₀,₅

T₀,₅ ⇒ The half-life of carbon 14 = 5730 years

T₀ = Time when the organism was alive

T₁ = Age of bones

Let us first calculate the radioactive decay constant.

λ = (Ln2)/T₀,₅

λ = 0.693/5730

λ = 0.0001209

Now, let us calculate the first term in the equation

Ln (C14T₁/C14 T₀) = Ln (0.1/0.23) = Ln 0.4347 = - 0.833

Finally, let us replace the terms, clear the equation, and calculate the value of T₁.

Ln (C14T₁/C14 T₀) = - λ T₁

- 0.833 = - 0.0001209 x T₁

T₁ = - 0.833 / - 0.0001209

T₁ = 6889.99 ≅ 6890 years

The bones are approximately 6890 years.

You can learn more about dating organic matter with carbon14 at

brainly.com/question/4149380

#SPJ1

6 0

2 years ago

What are the building blocks of DNA And RNA

Paul [167]

The basic building block of DNA and RNA are Nucleotides.

3 0

3 years ago

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Describe the evolution of modern whales and dolphins using the fossil evidence

HACTEHA [7]

Whales are related back to a hairy, 4-legged land mammal that eventually led to the formation of flippers without phalanges, a blow hole that became more dorsal, and other defining features. All of this has been backed by fossil evidence, especially that found within a certain desert region (can’t remember the name) that has a vast amount of whale fossils from many different time periods

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3 years ago

The stage of infection from the time a pathogen enters your body until symptoms appear is known as the _______________ stage.

Sophie [7]

Incubation stage is the stage where the prepares and begins a full on assault of your body.

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3 years ago