Answer:
y = x + 1 which is marked by the broken line
At the end of each year, the amount is (1 + 11%) = 1.11 times the amount at the beginning of the year. When that multiplier is applied 5 times, the result is
$30 * 1.11^5 ≈ $50.55
Answer:
a.) b⁷÷b⁴
= <u>b⁷</u>
b⁴
= b^7-4
= b³
b.) <u>x </u><u> </u><u>×</u><u> </u><u> </u><u>x⁵</u>
x² × x
= <u>x</u><u>^</u><u>1+</u><u>5</u>
x^2+1
= <u>x⁶</u>
x³
= x^6-3
= x³
Let's call n the number of days Marika's been training for the race, and
the distance she runs on the nth day in meters. After the first day, when n = 1, she runs 100 meters, so

On the second day, she runs an additional 4 meters, on the third day, another 4, and so on. Here's what that looks like mathematically:

It would be easier to write this continued addition as multiplication, in which case those same equations would look like

Notice that, in every case, the number 4 is being multiplied by is 1 less than n. We could even write for our first term that
. In general, we can say that

Which is expressed by option B.
(Bonus: What piece of information from this question did we not need to use here?)