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Tamiku [17]
3 years ago
11

Which expressions are equivalent to Negative 9 (two-thirds x + 1)? Check all that apply. − 9 ⋅ ( 2 3 x ) + 9 ( 1 ) − 9 ⋅ ( 2 3 x

) − 9 ( 1 ) − 6 x + 9 − 9 ⋅ ( 2 3 x ) + 1 − 6 x − 9 − 6 x + 1
Mathematics
1 answer:
aleksley [76]3 years ago
7 0

Answer:

•(-9 × 2x/3 + 1 × -9)

•-6x - 9

Step-by-step explanation:

Which expressions are equivalent to Negative 9 (two-thirds x + 1)?

Check all that apply.

Negative 9 (two-thirds x + 1) can be expressed as:

-9(2/3x + 1)

Expanding the brackets

(-9 × 2x/3 + 1 × -9)

-6x - 9

Therefore, the expressions that are equivalent to Negative 9 (two-thirds x + 1) is:

•(-9 × 2x/3 + 1 × -9)

•-6x - 9

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In the state of Arkansas, Muscadine grapes are a very popular fruit for making jam and jelly. Michael began growing the fruit mo
KatRina [158]

Answer:

The percentage of error in the question is 75%.

Step-by-step explanation:

To find the percentage of error, we need to subtract the actual value from the value that was expected, divide the result by the expected value.

He predicted that the crop would produce 8 bushels so this is our expected value. The actual value, which is the number of bushels produced, is 14.

  • If we make the calculation (14 - 8) / 8 = 6 / 8.
  • And then multiply the result by 100 to find the percentage, (6 / 8) x 100 = 75.

So the percentage of error in the question is 75%.

I hope this answer helps.

6 0
3 years ago
HELP ME WITH MATH HOMEWORK please 11points㋛㋛
Korvikt [17]

Answer:

7. Option B:40 is the correct answer.

8. Option D: y = 40x+75 is the correct answer.

Step-by-step explanation:

Given that:

Charges per hour = $40

Fee charged by repairman = $75

x = number of hours

y = total fee

According to given statement;

y = 40x+75

The standard equation is

y = mx + b

On comparing;

Slope of the line is given by m, therefore

Slope = m = 40

Hence,

7. Option B:40 is the correct answer.

8. Option D: y = 40x+75 is the correct answer.

5 0
3 years ago
If α and β are the zeroes of the polynomial 6y 2 − 7y + 2, find a quadratic polynomial whose zeroes are 1 α and 1 β .
ollegr [7]

Answer:

2y^2-7y+6=0

Step-by-step explanation:

We are given that \alpha and \beta are the zeroes of the polynomial 6y^2-7y+2

y^2-\frac{7}{6}y+\frac{1}{3}

We have to find a quadratic polynomial whose zeroes are 1/\alpha and 1/\beta.

General quadratic equation

x^2-(sum\;of\;zeroes)x+ product\;of\;zeroes

We get

\alpha+\beta=\frac{7}{6}

\alpha \beta=\frac{1}{3}

\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha \beta}

\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7/6}{1/3}

\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7}{6}\times 3=7/2

\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{\alpha \beta}

\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{1/3}=3

Substitute the values

y^2-(7/2)y+3=0

2y^2-7y+6=0

Hence, the quadratic polynomial whose zeroes are 1/\alpha and 1/\beta is given by

2y^2-7y+6=0

4 0
4 years ago
Help me please thank you
lubasha [3.4K]
D..............................
6 0
3 years ago
What's the answer<br> to this please help
givi [52]

Answer:

Question 11 is correct (7.9).
Question 12 is not 8.3, it is 9.6.

Step-by-step explanation:

5 0
3 years ago
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