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Makovka662 [10]

2 years ago

9

What is the value of the expression shown below? 2 over 3 to the power of 2 + 5 × 2 − 4 (4 points)

1 answer:

kondor19780726 [428]2 years ago

6 0

Answer: It equals 8.

Step-by-step explanation:

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Madeline works as a part time job at Parkland Hospital for $20 per hour. She worked for 10 hours last week and must pay 10% in t

ioda

Answer:

20

Step-by-step explanation:

20 x 10 = 200

10% = 0.10

200 x 0.10 = 20

7 0

3 years ago

Read 2 more answers

Find the value of x which satisfies the following equation.<br> log2(x−1)+log2(x+5)=4

weqwewe [10]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: x = 3$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: log_{2}(x - 1) log_{2}(x + 5) = 4$

$\qquad \tt \rightarrow \: log_{2} \{(x - 1)(x + 5) \} = 4$

[ log (x) + log (y) = log (xy) ]

$\qquad \tt \rightarrow \: ( x - 1)(x + 5) = {2}^{4}$

$\qquad \tt \rightarrow \: {x}^{2} + 5x - x - 5 = 16$

$\qquad \tt \rightarrow \: {x}^{2} + 4x - 5 - 16 = 0$

$\qquad \tt \rightarrow \: {x}^{2} + 4x -21 = 0$

$\qquad \tt \rightarrow \: {x}^{2} + 7x - 3x - 21 = 0$

$\qquad \tt \rightarrow \: x(x + 7) - 3(x + 7) = 0$

$\qquad \tt \rightarrow \: (x + 7)(x - 3) = 0$

$\qquad \tt \rightarrow \: x = - 7 \: \: or \: \: x = 3$

The only possible value of x is 3, since we can't operate logarithm with a negative integer in it.

$\qquad \tt \rightarrow \: x = 3$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

4 0

1 year ago

I need help what’s the answer?

KonstantinChe [14]

Answer:

hi

Step-by-step explanation:

hi

3 0

2 years ago

) A store is having a 30% off sale. Michelle uses the expression 0.7p and Stuart uses the expression p-0.3p. Who is using the co

Aleonysh [2.5K]

Answer:michelle

Step-by-step explanation: it is 70% of the cost since it’s 30% of the original

3 0

2 years ago

Write (1/3i)-(-6+2/3i) as a complex number in standard form

Eddi Din [679]

Answer:

$6+\frac{i}{3}$

Step-by-step explanation:

$\frac{1}{3\imath}-(-6+\frac{2}{3\imath})$

$\frac{1}{3\imath}+6-\frac{2}{3\imath}$

taking like terms together

$\frac{1}{3\imath}-\frac{2}{3\imath}+6$

taking LCM

$\frac{1-2}{3\imath}+6$

$\frac{-1}{3\imath}+6$

taking LCM

$\frac{-1+18\imath}{3\imath}$

splitting the term

$\frac{-1+18\imath}{3\imath}$

splitting the term

$-\frac{1}{3\imath}+\frac{18\imath}{3\imath}$

$-\frac{1\times3\imath}{3\imath \times \imath}+6$

$-\frac{i}{3\imath^2}+6$

we know that

$\imath^2=-1$

putting this value in above equation

$\frac{\imath}{3}+6$

7 0

2 years ago