Answer:
Place the compass at one end of line segment.
Adjust the compass to slightly longer than half the line segment length.
Draw arcs above and below the line.
Keeping the same compass width, draw arcs from other end of line.
Place ruler where the arcs cross, and draw the line segment.
Answer:
No.
Step-by-step explanation:
It is not because 20 is not a perfect square.
Answer 5.5
Explanation 125 + 125= 250
250 + 50=300
Is 2 125s and 1 50
Each 125 is 2.5
But in this case there is 2 125s
2.5+2.5=5
plus the other half = 5.5
BRAINLIST?
Answer:
The regular price of the balls is $8
Step-by-step explanation:
The sporting goods store sales promotion is as follows;
The price of the third ball after buying two balls at regular price = $1.00
The price of the number of balls Coach John pays for the balls he bought = $136
To buy 24 balls, we have;
2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1
Therefore;
The number of balls bought at regular price = The sum of the 2s = 16 balls
The number of balls bought for $1 = 24 - 16 = 8 balls
Let x represent the regular price of the balls, we have;
16 × x + 8 = 136
16·x = 138 - 8 = 128
x = 128/16 = 8
The regular price of the balls = x = $8.
Answer:
a) see the plots below
b) f(x) is exponential; g(x) is linear (see below for explanation)
c) the function values are never equal
Step-by-step explanation:
a) a graph of the two function values is attached
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b) Adjacent values of f(x) have a common ratio of 3, so f(x) is exponential (with a base of 3). Adjacent values of g(x) have a common difference of 2, so g(x) is linear (with a slope of 2).
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c) At x ≥ 1, the slope of f(x) is greater than the slope of g(x), and the value of f(x) is greater than the value of g(x), so the curves can never cross for x > 1. Similarly, for x ≤ 0, the slope of f(x) is less than the slope of g(x). Once again, f(0) is greater than g(0), so the curves can never cross.
In the region between x=0 and x=1, f(x) remains greater than g(x). The smallest difference is about 0.73, near x = 0.545, where the slopes of the two functions are equal.