Answer:
c
Step-by-step explanation:
Step 1
Solve 3x-y=-63x−y=−6 for yy.
y=6+3xy=6+3x
Step 2
Substitute 6+3x6+3x for yy in the second and third equation.
2\left(6+3x\right)-5z=-52(6+3x)−5z=−5 x-\left(6+3x\right)-2z=-4x−(6+3x)−2z=−4
Step 3
Solve these equations for xx and zz respectively.
x=-\frac{17}{6}+\frac{5}{6}zx=−
6
17
+
6
5
z z=-1-xz=−1−x
Step 4
Substitute -\frac{17}{6}+\frac{5}{6}z−
6
17
+
6
5
z for xx in the equation z=-1-xz=−1−x.
z=-1-\left(-\frac{17}{6}+\frac{5}{6}z\right)z=−1−(−
6
17
+
6
5
z)
Step 5
Solve z=-1-\left(-\frac{17}{6}+\frac{5}{6}z\right)z=−1−(−
6
17
+
6
5
z) for zz.
z=1z=1
Step 6
Substitute 11 for zz in the equation x=-\frac{17}{6}+\frac{5}{6}zx=−
6
17
+
6
5
z.
x=-\frac{17}{6}+\frac{5}{6}\times 1x=−
6
17
+
6
5
×1
Step 7
Calculate xx from x=-\frac{17}{6}+\frac{5}{6}\times 1x=−
6
17
+
6
5
×1.
x=-2x=−2
Step 8
Substitute -2−2 for xx in the equation y=6+3xy=6+3x.
y=6+3\left(-2\right)y=6+3(−2)
Step 9
Calculate yy from y=6+3\left(-2\right)y=6+3(−2).
y=0y=0
Step 10
The system is now solved.
x=-2x=−2 y=0y=0 z=1z=1
Solution
x=-2x=−2
y=0y=0
z=1z=1
The answer is 8 because 2x2x2=8
Okay ShallBeTheLast, what we will do will involve a lot of simple plug and play kind of actions.
To start we must notice one number must be negative and the other should be positive, because the multiplied number is a negative.
Next, lets multiply number that have a sum of 10 (keep in mind one has to be negative and the other has to be positive).
-1 * 10 = -10 false
-2 * 12 = -24 false
-3 * 13 = -39 false
notice that no number working and it's only getting farther away.
There is no solution for this that involves to integers.
I think you might of wrote the question backwards.
If that is the case we would run numbers like.....
-1 * (-6) = 7 false
-2 * (-5) = 10 true!!!!
-2 and -5 would work
First In First Out.
FIFO intends to sell the first one that comes through the door first, and that item will be the oldest one in the inventory, so the old one gets sold first.
so it doesn't assume to sell the new one first.
