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avanturin [10]
3 years ago
5

6. Write an algebraic expression for the word phrase 5 times the product of x and y

Mathematics
2 answers:
Lena [83]3 years ago
8 0

Answer:

5+x=y ,x-y=5,y-x=5,5-x=y,y+5=x

Step-by-step explanation:

Dmitry [639]3 years ago
3 0

5 times the product of x and y = 5xy

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Which of the following describes the transformation from Figure 1 to Figure 2?
Mrrafil [7]

9514 1404 393

Answer:

  Rotation 90° CCW

Step-by-step explanation:

Note that Figure 1 has a small appendage off the larger rectangle. That appendage is pointing East (to the right).

In Figure 2, that same appendage is pointing North (up).

If you are facing East and you want to face North, you will find that you need to turn 90° in the counterclockwise direction. That is the transformation that was done here:

  rotation 90° CCW about the origin

3 0
3 years ago
Read 2 more answers
Can you solve it, please
weeeeeb [17]

Answer:20

Step-by-step explanation:

3.1 *4.2=13.02 12.4*21=260.4 260.4/13.02=20

8 0
2 years ago
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Bob need to mix 2 cups of orange juice concentrate with 3.5 cups of water to make orange juice. bob has 6 cups of concentrate. h
USPshnik [31]
3 x 2 = 6 cups of concentrate

3.5 x 3 = 10.5 cups of water  



Bob can make 6 cups of orange juice.
8 0
3 years ago
Read 2 more answers
Helppp me plsssssssss<br><br>​
Oliga [24]

Answer:

The class 35 - 40 has maximum frequency. So, it is the modal class.

From the given data,

  • \sf \:\:\:\:\:\:\:\:\:\:x_{k}=35
  • \sf \:\:\:\:\:\:\:\:\:\:f_{k}=50
  • \sf \:\:\:\:\:\:\:\:\:\:f_{k-1}=34
  • \sf \:\:\:\:\:\:\:\:\:\:f_{k+1}=42
  • \sf \:\:\:\:\:\:\:\:\:\:h=5

{\bf \:\: {By\:using\:the\: formula}} \\ \\

\:\dag\:{\small{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}}} \\ \\

\sf \:\:\:\:\:\:\:\:\:= 35+ {\bigg(5 \times \dfrac{(50 - 34)}{ ( 2 \times 50 - 34 - 42)}\bigg)} \\ \\

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 35 +{\bigg(5 \times \dfrac{16}{24}\bigg)} \\ \\

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= {\bigg(35+\dfrac{10}{3}\bigg)} \\ \\

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(35 + 3.33) =.38.33 \\ \\

\:\:\sf {Hence,}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \large{\underline{\mathcal{\gray{ mode\:=\:38.33}}}} \\ \\

{\large{\frak{\pmb{\underline{Additional\: information }}}}}

MODE

  • Most precisely, mode is that value of the variable at which the concentration of the data is maximum.

MODAL CLASS

  • In a frequency distribution the class having maximum frequency is called the modal class.

{\bf{\underline{Formula\:for\: calculating\:mode:}}} \\

{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}} \\ \\

Where,

\sf \small\pink{ \bigstar} \: x_{k}= lower\:limit\:of\:the\:modal\:class\:interval.

\small \blue{ \bigstar}\sf \: f_{k}=frequency\:of\:the\:modal\:class

\sf \small\orange{ \bigstar}\: f_{k-1}=frequency\:of\:the\:class\: preceding\:the\;modal\:class

\sf \small\green{ \bigstar}\: f_{k+1}=frequency\:of\:the\:class\: succeeding\:the\;modal\:class

\small \purple{ \bigstar}\sf \: h= width \:of\:the\:class\:interval

7 0
3 years ago
What is the geometric mean between 9/16 and 25/36
sergiy2304 [10]

Answer:

5/8

Step-by-step explanation:

Geometric mean is found by multiplying the n number of values and then taking the n-root.

To do this with these numbers, sqrt((9/16)*(25/36)) = (3/4)(5/6) = (1/4)(5/2)= 5/8

I hope this helps! :)

6 0
2 years ago
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