Question

Given: <B and <D are right angles;C is the midpoint of BD.Prove:ΔABC =ΔEDC​

Answer 1

Step-by-step explanation:

Statements Reasons

In $\triangle ^{s}$ ABC and EDC

1.$\angle \: ABC = \angle \: CDF [ A ]$ Both are 90° [ Given }

2. BC = CD [ S ] C is the midpoint of BD [ Given ]

3. $\angle \: BAC = \angle \: CED [ A ]$ Alternate angles

4. $\triangle ABC \cong \triangle \: EDC \:$ By AAS axiom

Hence Proved !

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