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kvv77 [185]
3 years ago
8

How many distinct "pieces" are in this graph?

Mathematics
1 answer:
snow_tiger [21]3 years ago
7 0

Answer:

2

Step-by-step explanation:

the first point and where the line turns

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Write a real world problem for 8x=48
Evgen [1.6K]

Answer:

the total number of profits made at the fair was $48. each person had to pay $8 to get in. how many people were at the fair

Step-by-step explanation:

8 0
3 years ago
Find the cosine of angle B.
Alexandra [31]

\boxed { \text {Cosine Rule : } a^2 = b^2 + c^2 - 2bc \cos(A) }

-

9² = 12² + 15² - 2 (12) (15) cos (B)

81 = 144 + 225 - 360 cos(B)

81 = 369 - 360 cos (B)

360 cos (B) = 369 - 81

360 cos (B) = 288

cos (B) = 0.8

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Answer: Cosine B = 0.8

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\boxed { \text {Cosine Rule : } a^2 = b^2 + c^2 - 2bc \cos(A) }

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12² = 15² + 9² - 2 (15)(9) cos (A)

144 = 225 + 81 - 270 Cos A

144 = 306 - 270 Cos A

270 Cos A = 162

Cos A = 3/5 or 0.6

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Answer: Cosine Angle A = 3/5

4 0
3 years ago
Find the simple interest on a $3,219.00 principal, deposited for six years at a rate of 1.51%.
Karo-lina-s [1.5K]

Answer:

s.i = P. T. R /100

= 3219 . 6 . 1.51 /100

= 29,164.14 / 100

= 291.6414

8 0
3 years ago
Which expression is equivalent to (3x² + 4x - 7)(x - 2)? (Apex)
katovenus [111]

Answer:

A i think

Step-by-step explanation:

3 0
3 years ago
[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation
irina1246 [14]

Answer:

y=-\frac{158}{579}

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]

And the vector B is formed with the solution of each equation of the system:b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called A_{2}.

A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]

The value of y using Cramer's rule is:

y=\frac{det(A_{2}) }{det(A)}

Find the value of the determinant of each matrix, and divide:

y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}

y=-\frac{158}{579}

7 0
3 years ago
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