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Aloiza [94]
3 years ago
8

Kelly arrives for work at a restaurant at 5:00 p.m. Once there, she washes and chops vegetables, then sets aside ingredients and

organizes them for the cook. Kelly is most likely a . Mark's work hours change every week, depending on when he is needed. He wears a suit and tie to work at an elegant restaurant. He greets guests and seats them in a waiting area. He then guides them to their tables. Mark is most likely a
Computers and Technology
2 answers:
kari74 [83]3 years ago
3 0

Answer:

ExplanKelly arrives for work at a restaurant at 5:00 p.m. Once there, she washes and chops vegetables, then sets aside ingredients and organizes them for the cook. Kelly is most likely a  

✔ Food Preparation Worker

.

Mark's work hours change every week, depending on when he is needed. He wears a suit and tie to work at an elegant restaurant. He greets guests and seats them in a waiting area. He then guides them to their tables. Mark is most likely a  

✔ Host

olganol [36]3 years ago
3 0

Answer:

✔ Food Preparation Worker ✔ Host

Explanation:

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Explanation:

a magazine cause it helps put out commercial

3 0
3 years ago
A new company will have 40 workstations in one building sharing a single network. All users must be able to share ¬les and print
kobusy [5.1K]

Answer:

Domain Networking.

Explanation:

A domain in networking refers to any group of workstation,users,printers devices ,database servers and computers which share different type of data via resources of network.

Hence domain networking will be the best option for the company having 40 workstation in a single building sharing a single network.

6 0
3 years ago
Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server
sattari [20]

Answer:

The smallest number of servers required is 3 servers

<em />

Explanation:

Given

Reliability = 99.98\%

Individual Servers = 95\%

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

p = 95\%\\

It should be noted that probabilities always add up to 1;

So,

p + q = 1'

Subtract p from both sides

p - p + q = 1 - p

q = 1 - p

Substitute p = 95\%\\

q = 1 - 95\%

Convert % to fraction

q = 1 - \frac{95}{100}

Convert fraction to decimal

q = 1 - 0.95

q = 0.05

------------------------------------------------------------------------------------------------

<em>To get an expression for one server</em>

The probabilities of 1 servers having 99.98% reliability is as follows;

p = 99.98\%

Recall that probabilities always add up to 1;

So,

p + q = 1

Subtract q from both sides

p + q - q = 1 - q

p = 1 - q

So,

p = 1 - q = 99.98\%

1 - q = 99.98\%

Let the number of servers be represented with n

The above expression becomes

1 - q^n = 99.98\%

Convert percent to fraction

1 - q^n = \frac{9998}{10000}

Convert fraction to decimal

1 - q^n = 0.9998

Add q^n to both sides

1 - q^n + q^n= 0.9998 + q^n

1 = 0.9998 + q^n

Subtract 0.9998 from both sides

1 - 0.9998 = 0.9998 - 0.9998 + q^n

1 - 0.9998 = q^n

0.0002 = q^n

Recall that q = 0.05

So, the expression becomes

0.0002 = 0.05^n

Take Log of both sides

Log(0.0002) = Log(0.05^n)

From laws of logarithm Loga^b = bLoga

So,

Log(0.0002) = Log(0.05^n) becomes

Log(0.0002) = nLog(0.05)

Divide both sides by Log0.05

\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}

\frac{Log(0.0002)}{Log(0.05)} = n

n = \frac{Log(0.0002)}{Log(0.05)}

n = \frac{-3.69897000434}{-1.30102999566}

n = 2.84310893421

n = 3 (Approximated)

<em>Hence, the smallest number of servers required is 3 servers</em>

6 0
3 years ago
Software that interprets commands from the keyboard and mouse is also known as the ​
Luda [366]

Answer:

THE OPERATING SYSTEM (OS)

Explanation:

6 0
4 years ago
Which one of the following analog VOM ranges would be selected to measure a DC
tensa zangetsu [6.8K]
<span>100 mA of course. You cannot use 10 mA because it will be over the range and the higher ranges are not accurate at 90 mA</span>
7 0
3 years ago
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