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Kobotan [32]
3 years ago
6

PLEASE HELP! NO LINKS!!What is the slope of the line in the graph?

Mathematics
1 answer:
marysya [2.9K]3 years ago
7 0
I would say -1/2 not sure though
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Vertical stretch by 2 units.

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3 years ago
A computer that originally cost $850 is on sale for 15%off. What is the sale price of the computer show your work
Yakvenalex [24]
If it is on sale for 15%, then you are paying 85% (100-15) of the original price.

To find 85% of 850, you do 850*.85 to get $722.50

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4 0
3 years ago
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Find the minimum and maximum possible areas for a rectangle measuring 4.15 cm by 7.34 cm. Round to the nearest hundredth. A. min
Shalnov [3]

This is probably in the context of a discussion of significant figures and accuracy.

When we record a measurement of 4.15 cm with two significant figures, that means we believe the exact value is in the range from 4.145 cm to  41.155 cm

Similarly 7.34 really means between 7.335 and 7.345 cm.

The minimum area rectangle is 

4.145 \times 7.335 = 30.403575 \approx 30.40

The maximum area rectangle is

4.155 \times 7.345 =30.518475 \approx 30.52

Choice A


5 0
3 years ago
Read 2 more answers
Identify this conic section.<br><br> 9x 2 + 4y 2 = 36
oksano4ka [1.4K]
Divide: 9x 2/36 - 4y 2/36 = 36/36. Simplify: x2/4 - y2/9 = 1. Then do (x-0) 2/4 - (y-0)2 =1. Hyperbola.
4 0
3 years ago
Which of the following are square roots of —8 + 8i/3? Check all that apply.
8090 [49]

Answer:

Options (2) and (3)

Step-by-step explanation:

Let, \sqrt{-8+8i\sqrt{3}}=(a+bi)

(\sqrt{-8+8i\sqrt{3}})^2=(a+bi)^2

-8 + 8i√3 = a² + b²i² + 2abi

-8 + 8i√3 = a² - b² + 2abi

By comparing both the sides of the equation,

a² - b² = -8 -------(1)

2ab = 8√3

ab = 4√3 ----------(2)

a = \frac{4\sqrt{3}}{b}

By substituting the value of a in equation (1),

(\frac{4\sqrt{3}}{b})^2-b^2=-8

\frac{48}{b^2}-b^2=-8

48 - b⁴ = -8b²

b⁴ - 8b² - 48 = 0

b⁴ - 12b² + 4b² - 48 = 0

b²(b² - 12) + 4(b² - 12) = 0

(b² + 4)(b² - 12) = 0

b² + 4 = 0 ⇒ b = ±√-4

                     b = ± 2i

b² - 12 = 0 ⇒ b = ±2√3

Since, a = \frac{4\sqrt{3}}{b}

For b = ±2i,

a = \frac{4\sqrt{3}}{\pm2i}

  = \pm\frac{2i\sqrt{3}}{(-1)}

  = \mp 2i\sqrt{3}

But a is real therefore, a ≠ ±2i√3.

For b = ±2√3

a = \frac{4\sqrt{3}}{\pm 2\sqrt{3}}

a = ±2

Therefore, (a + bi) = (2 + 2i√3) and (-2 - 2i√3)

Options (2) and (3) are the correct options.

6 0
3 years ago
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