Question

A load of 600N is lifted using a first class lever applying an effort of 350N .If the distance between the load and the effort is 60 cm and the distance between the load and the fulcrum is 30cm,calculate its efficiency
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Answer 1

Answer:

Efficiency = 85.5%

Explanation:

Given the following data;

Load = 600N

Effort = 350N

To find the efficiency of the lever, we would first of all determine the mechanical advantage and velocity ratio.

$Mechanical \; advantage = \frac {Load}{Effort}$

Substituting into the equation, we have;

$Mechanical \; advantage = \frac {600}{350}$

Mechanical advantage = 1.71

$Velocity \; ratio = \frac {Distance \; moved \; by \; effort}{Distance \; moved \; by \; load}$

Substituting into the equation, we have;

$Velocity \; ratio = \frac {60}{30}$

Velocity ratio = 2

Now, to find the efficiency of the lever

$Efficiency = \frac {Mechanical \; advantage}{Velocity \; ratio} * 100$

Substituting into the equation, we have;

$Efficiency = \frac {1.71}{2} * 100$

$Efficiency = 0.855 * 100$

Efficiency = 85.5%