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3 years ago

Please solve number 6

Mathematics

1 answer:

Vesnalui [34]3 years ago

8 0

Answer:

#6 is 36

Step-by-step explanation:

A=b h=9·4=36

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84 out of 240 what is the percentage

Nesterboy [21]

Convert fraction (ratio) 84 / 240 Answer: 35%

5 0

3 years ago

Read 2 more answers

At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a

morpeh [17]

Answer: a) 4.6798, and b) 19.8%.

Step-by-step explanation:

Since we have given that

P(n) = $\dfrac{15}{120}=0.125$

As we know the poisson process, we get that

$P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda$

So, for exactly one car would be

P(n=1) is given by

$=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599$

Hence, our required probability is 0.2599.

a. Approximate the number of these intervals in which exactly one car arrives

Number of these intervals in which exactly one car arrives is given by

$0.2599\times 18=4.6798$

We will find the traffic flow q such that

$P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr$

b. Estimate the percentage of time headways that will be 14 seconds or greater.

so, it becomes,

$P(h\geq 14)=e^{\frac{-qt}{3600}}\\\\P(h\geq 14)=e^{\frac{-415.88\times 14}{3600}}\\\\P(h\geq 14)=0.198\\\\P(h\geq 14)=19.8\%$

Hence, a) 4.6798, and b) 19.8%.

7 0

4 years ago

I need help with 5&6 please ASAP!!!!!!!

Elenna [48]

Hi BFFF IM MDJXJCNDM

4 0

3 years ago

Read 2 more answers

If anybody answers these questions I will get them brainliest and if somebody else verifies that it is the correct answer I can

valina [46]

Part (a)

<h3>Answer: x^3 + 12x^2 + 47x + 60</h3>

--------------------------

Work Shown:

Let's say we have

L = length = x+5
W = width = x+4
H = height = x+3

To find the volume of the block, we multiply the length width and height.

So,

volume = (length)*(width)*(height)

V = L*W*H

V = LW*(x+3) .... replace H with (x+3)

V = LW*x + LW*3 .... distribute

V = Lx*(W) + 3L*(W)

V = Lx(x+4) + 3L(x+4) .... replace W with x+4

V = Lx^2 + 4Lx + 3Lx + 12L .... distribute

V = Lx^2 + 7Lx + 12L

V = x^2*(L) + 7x*(L) + 12*(L)

V = x^2*(x+5) + 7x*(x+5) + 12*(x+5) .... replace L with x+5

V = x^3 + 5x^2 + 7x^2 + 35x + 12x + 60 .... distribute

V = x^3 + 12x^2 + 47x + 60

x^3 + 12x^2 + 47x + 60 is the polynomial in standard form that represents the volume of the block.

=======================================================

Part (b)

<h3>Answer: 336 cubic feet</h3>

--------------------------

Work Shown:

We can plug x = 3 into the polynomial we found

V = x^3 + 12x^2 + 47x + 60

V = (3)^3 + 12(3)^2 + 47(3) + 60

V = 27 + 12(9) + 47(3) + 60

V = 27 + 108 + 141 + 60

V = 336

Or we could find the volume like this

V = L*W*H

V = (x+5)*(x+4)*(x+3)

V = (3+5)*(3+4)*(3+3)

V = (8)*(7)*(6)

V = 336

Either way, we get the same volume of 336 cubic feet.

3 0

3 years ago

PLS HELP ASAP. NO LINKS <br> When z= 9, the value of z2 + 1 is

elena55 [62]

Answer is 82

substitute z for 9

9^2 = 81+ 1= 82

6 0

3 years ago