The probability he will select a hockey card is 1/4, and then the probability that he selects a baseball card without replacement is 1/6.
You want to find out the probability of getting a 2 first and getting a 3 on a fair dice;
P(rolling 2 and 3)= (1/6)(1/6) <-- knowing that rolling a 2 has a possibility of 1/6, same with rolling a 3.
Therefore, the probability of getting a 2 and a three or 3 and a two is 1/36
Hope I helped :)
I think the answer is 10 because:
6x2=12
12+2x-32=0
make the like terms together = 12-32+2x=0
= -20+2x=0
again make the like terms together = 2x=0+20 [sign changes when it goes to the other side]
so, 2x=20
x=20/2 [ multiplication will change into division when it goes to the other side]
therefore x=10
Answer:
Step-by-step explanation:
Given
Required
Determine the length of FG
Since, F is on segment EG, then
Substitute values for EG, EF and FG
Collect Like Terms
Solve for x
Substitute 7 for x in
