SmArT pEoPlE aNsWeR Yess ʸᴱˢ

Find the value of x

fgiga [73]

$\qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star$

x = 35°

$\textsf{ \underline{\underline{Steps to solve the problem} }:}$

$\qquad❖ \: \sf \:4x + 1 + x + 4 = 180$

[ by linear pair ]

$\qquad❖ \: \sf \:5x + 5 = 180$

$\qquad❖ \: \sf \:5(x + 1) = 180$

$\qquad❖ \: \sf \:x + 1 = 180 \div 5$

$\qquad❖ \: \sf \:x + 1 = 36$

$\qquad❖ \: \sf \:x = 36 - 1$

$\qquad❖ \: \sf \:x = 35$

$\qquad \large \sf {Conclusion} :$

x = 35°

7 0

1 year ago

— 4x — Зу = = 9<br> 5х = 15<br> Help me now

blsea [12.9K]

Answer:

y=-7

x=3

Step-by-step explanation:

I just used a calculator. Hope this helps. :)

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=3%28y%20-%209%29%20%3D%2030" id="TexFormula1" title="3(y - 9) = 30" alt="3(y - 9) = 30" align=

Ira Lisetskai [31]

Answer:

y=19

Step-by-step explanation:

3(y - 9) = 30

3y - 27 = 30

3y = 30 + 27

3y = 57

y = 19

brainliest?

4 0

2 years ago

Define z_alpha to be a z-score with an area of alpha to the right. For Example: z_0.10 means P(Z > z_0.10) = 0.10. We would a

Reptile [31]

Answer:

a) P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

And for this case the two values are : $z_{crit}= \pm 1.96$

b) P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates $\alpha/2$ of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

c) For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got $z_{\alpha/2}=1.64$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Part a

P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

And for this case the two values are : $z_{crit}= \pm 1.96$

Part b

P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates $\alpha/2$ of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

Part c

For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got $z_{\alpha/2}=1.64$

6 0

3 years ago

Can someone plz help me plz I beg u

erastovalidia [21]

Answer:

12.5663

Step-by-step explanation:

3 0

2 years ago

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