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2 years ago

SmArT pEoPlE aNsWeR Yess ʸᴱˢ

Mathematics

2 answers:

almond37 [142]2 years ago

8 0

Answer:D

Step-by-step explanation:

Because you have to combine like terms first

Nata [24]2 years ago

7 0

Answer:

D. Rewrite 2x + 4x as 6x

Step-by-step explanation:

Doing A,B,C will just give you the wrong answer; I don't know how to explain it better. I promise I'm smart:I'm in advanced mathematics and language arts :)

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Which is the length of the hypotenuse of the triangle?

Pepsi [2]

Since this is a right triangle, we can use the Pythagorean Theorem, which states a² + b² = c² in a right triangle.

Plugging our numbers in, we get:

(12)² + (35)² = c²

From there, we can square the numbers.

(144) + (1225) = c²

Then, we can add them together to find the sum;

(1369) = c²

And finally, we can find the square root of both sides.

(37) = c

Therefore, 37 is the answer and your answer choice is correct.

5 0

2 years ago

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Find f (-2), f(0), and f(3)

Komok [63]

Answer:

f en el chat box

Step-by-step explanation:

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2 years ago

Identify the polygon with vertices A(5,0), B(2,4), C(−2,1), and D(1,−3), and then find the perimeter and area of the polygon. HE

inn [45]

Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to $20\ units$

Part 3) The area is equal to $25\ units^{2}$

Step-by-step explanation:

we have

$A(5,0), B(2,4), C(-2,1),D(1,-3)$

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$A(5,0),B(2,4)$

substitute in the formula

$d=\sqrt{(4-0)^{2}+(2-5)^{2}}$

$d=\sqrt{(4)^{2}+(-3)^{2}}$

$d=\sqrt{25}$

$AB=5\ units$

Find the distance BC

$B(2,4), C(-2,1)$

substitute in the formula

$d=\sqrt{(1-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$BC=5\ units$

Find the distance CD

$C(-2,1),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-4)^{2}+(3)^{2}}$

$d=\sqrt{25}$

$CD=5\ units$

Find the distance AD

$A(5,0),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-0)^{2}+(1-5)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$AD=5\ units$

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

$B(2,4),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-4)^{2}+(1-2)^{2}}$

$d=\sqrt{(-7)^{2}+(-1)^{2}}$

$BD=\sqrt{50}\ units$

Verify if the polygon is a square

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

$BD^{2}=AD^{2}+AB^{2}$

substitute

$(\sqrt{50})^{2}=5^{2}+5^{2}$

$50=50$ -----> is true

The triangle BDA is a right triangle

therefore

The polygon is a square

Find the Area of the polygon

The area of a square is equal to

$A=b^{2}$

we have

$b=5\ units$

$A=5^{2}=25\ units^{2}$

Find the perimeter of the polygon

The perimeter of a square is equal to

$P=4b$

we have

$b=5\ units$

$P=4(5)=20\ units$

6 0

2 years ago

What is the system of equations for 2x + 2y = 10 and 5x - 2y=4?

vagabundo [1.1K]

$2x + 2y = 10 \\ 5x - 2y = 4 \\ 7x = 14 \\ x = 2 \\ \\ 2(2) + 2y = 10 \\ 4 + 2y = 10 \\ 2y = 6 \\ y = 3$
(2,3)

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2 years ago

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Ram, Shyam and Mohan purchased biscuits of different brands P, Q and R.

Alexxandr [17]

Answer:

Ram needs to pay $93

Shyam needs to pay $116

Mohan needs to pay $99

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2 years ago