ANSWER: 32 five-dollar bills
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EXPLANATION:
Let x be number of $5 bills
Let y be number of $10 bills
Since we have total of 38 bills, we must have the sum of x and y be 38
x + y = 38 (I)
Since the total amount deposited is $220, we must have the sum of 5x and 10y be 220 (x and y are just the "number of" their respective bills, so we multiply them by their value to get the total value):
5x + 10y = 220 (II)
System of equations:

Divide both sides of equation (II) by 5 so our numbers become smaller

Rearrange (I) to solve for y so that we can substitute into (II)

Substituting this into equation (II) for the y:

We have 32 five-dollar bills
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If we want to finish off the question, use y = 38 - x to figure out number of $10 bills

32 five-dollar bills and 6 ten-dollar bills
I believe it is negative 2/2, hope this helps you out.
move the decimal point two places to the right and the answer would be 56.4%
Answer:
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Step-by-step explanation:
From the question we are told that:
Mass 
Amount of NaCl IV 
Rate 
Generally the equation for fluid rate be for your IV pump is mathematically given by

Since
Rate is
30ml/kg/hr at 1kg patient Weight
Therefore

