To answer this, we need to start with the standard equation for an ellipse:
(x^2/a^2)+(y^2/b^2)=1
Where a is one half of one axis, and b is one half of the other.
The problem states that one axis is 1057 ft, and the other is 880 ft, so divide these values by 2 and square them. This results in:
(x^2/279,312.25)+(y^2/193,600)=1
For verification, if you have a graphing calculator, solve for y, set the size of the window so it should perfectly fit the ellipse, and check (it does)
Answer:
if 'c' equals number of counters, the answer is 6c + 5
Step-by-step explanation:
david has 'c'
lisa has '5+c'
samia has '4c'
add all terms together: c + 5 + c + 4c = 6c + 5
Answer:
first he had M some unknown amount
then he had 2/3 M since he spent 1/3 M
then he spent 3/4 of the (2/3 M) so he had 1/4 of the ( 2/3M)
then he spent what was left $20 so $20 = 1/4 ( 2/3 M) now solve for M
and check by doing each step and figuring how much was spent and how much left.
<u>another</u><u> </u><u>method</u><u> </u>
let us consider the left amount be Y and total now of M dollar be X
then
Y = amount of money Nartin has left
Y = X - ( 1/3 ) ( X ) - ( 3/4 ) ( X - 1/3 X ) - 20
Y = X - 1/3 X - 3/4 X + 3/12 X - 20
Y = X - 4/12 X - 9/12 X + 3/12 X - 20
Y = X - 10/12 X - 20
Y = X - 5/6 X - 20
Y = ( 1 / 6 ) ( X ) - 20
<u>hope</u><u> </u><u>it</u><u> </u><u>helped</u><u> </u><u>u</u><u> </u><u>buddy</u><u> </u><u /><u>:</u><u> </u><u>)</u>
D. the number of phone calls.
One day there could be 80 phone calls and the next there could be 2. It is continuously random.