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Finger [1]
3 years ago
9

A. f(1.3)=1. B. f(1.8)=2 c. f(-1.5)=-2 D. f(2.8)=2

Mathematics
1 answer:
dimulka [17.4K]3 years ago
7 0
What’s the question?
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3 years ago
The factorization of 8x3 -125 is (2x-5)(jx2 +kx+25)
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\bf ~\hspace{10em}\textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) ~\hfill a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 8x^3-125~~ \begin{cases} 8=2\cdot 2\cdot 2\\ \qquad 2^3\\ 125=5\cdot 5\cdot 5\\ \qquad 5^3 \end{cases}\implies 2^3x^3-5^3\implies (2x)^3-5^3 \\[2em] [2x-5][(2x)^2+(2x)(5)+5^2]\implies (2x-5)(\stackrel{\stackrel{j}{\downarrow }}{4}x^2+\stackrel{\stackrel{k}{\downarrow }}{10}x+25)

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4 years ago
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