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3 years ago

Please help, I’m stuck on this question :)

Mathematics

1 answer:

tigry1 [53]3 years ago

8 0

Answer:

4 degrees maybe I've never done this

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How do u solve ssystem of equations using substitution

andrew11 [14]

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3 years ago

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Size Cost 4R = $0.25 per photo 5R = $0.50 Per photo 6R = $0.80 per photo A school ordered 308 photos of size 4R and some photos

lbvjy [14]

Answer:

0.25×308=$77

185-77=$108

108/0.50×1

=216photos

Total photos=216+308

=524photos

Step-by-step explanation:

3 0

3 years ago

Can someone answer this question for me

Margarita [4]

$18.75, i’m pretty sure :)

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3 years ago

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I don’t know how I would simply this

zlopas [31]

It is 11m+8

You just combine like terms

7 0

3 years ago

Answer. it fast please

mojhsa [17]

Answer:

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}$

Step-by-step explanation:

Given

$(\frac{6}{10})^3 * (\frac{5}{9})^2$

Required

Solve:

$(\frac{6}{10})^3 * (\frac{5}{9})^2$

Simplify 6/10

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{9})^2$

Express 9 as 3^2

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{3^2})^2$

Apply law of indices

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{(3^2)^2}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{3^4}$

Express as a sing;e fraction

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3*5^2}{5^3*3^4}$

Apply law of indices:

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^{3-2}*3^{4-3}}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^1*3^1}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5*3}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}$

5 0

3 years ago