A role-playing game uses an 11-sided die that displays the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 What is the probability tha
kondor19780726 [428]
Using it's concept, it is found that there is a 27.3% probability that someone throws the 11-sided die one time and rolls a number 9 or higher.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
In this problem, there are 11 numbers, 3 of which are 9 or higher, hence the probability is:
p = 3/11 = 0.273 = 27.3%.
More can be learned about probabilities at brainly.com/question/14398287
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Answer:
3x - 3
Step-by-step explanation:
(x + 4) + (2x - 7) =
The first step is to drop the parentheses since they are unnecessary.
= x + 4 + 2x - 7
Now group like terms together.
= x + 2x + 4 - 7
Combine like terms.
= 3x - 3
The nth root of a is always positive unless, a < 0 and "n" is an odd number. Also if a < 0 <span> and "n" is an even number, then it's an imaginary number. I hope this helps a lot</span>
Answer:
98?
Step-by-step explanation:
that your best shot id.....
Answer:
x>125
Step-by-step explanation:
multiply the denominator 25 on both sides
the "x" should cancel out
and then you would get x>125
