Answer:
The roots of the equation are x =
and x = 
and there are no real roots of the equation given above
Step-by-step explanation:
To solve:
5x² − 3x + 17 = 9
or
⇒ 5x² − 3x + 17 - 9 = 0
or
⇒ 5x² − 3x + 8 = 0
Now,
the roots of the equation in the form ax² + bx + c = 0 is given as:
x = 
in the above given equation
a = 5
b = -3
c = 8
therefore,
x = 
or
x = 
or
x =
and x = 
or
x =
and x = 
here i = √(-1)
Hence,
The roots of the equation are x =
and x = 
and there are no real roots of the equation given above
Answer:
Increase the potential of charges in the circuit
Step-by-step explanation:
Hope this is correct
HAVE A GOOD DAY!
Answer:
D/z
Step-by-step explanation:
Since D and z are variables, we can express the division as a fraction:
D/z
Answer:
Option D is correct
The approximate liquid volume of 5 of these bottles is, 15,000 milliliters.
Step-by-step explanation:
Given the statement: The liquid volume of Eric's water bottle is 3 liters.
Using conversion:
1 liters = 1000 milliliters
Convert 3 liters into milliliters;
using above conversion:
3 liters =
milliliters.
To find the volume of liquid in 5 of these bottles in milliliters:
Volume of liquid in 1 bottle is, 3000 milliliters.
then;
Volume of liquid in 5 bottles =
milliliters.
Therefore, approximate liquid volume of 5 of these bottles is, 15,000 milliliters
A) (-2,4)
first multiply 2nd eqn by 2 and subtract it from eqn 1st then u will get x then put x in ist eqn then u will get y.