I am so sorry this is the wrong answer
It would be no, because there is a lot of variability in the computer science book. Hope I help!
In order to find the price per bar, we divide the price by the amount of bars. For the first one:
15.37/10 = $1.54 per bar
The second package:
15.35/12 = $1.28 per bar.
The 10-pack costs $1.54 per bar and the 12-pack costs $1.28 per bar. The 12-pack has the better price per bar.
Now, let's look at the price per ounce. We do this in a similar way. We find the total amount of ounces in the package, and divide the price by the number of ounces.
In the first package, we multiply 10*2.1=21. We have 21 ounces in the first package. Now we divide 15.37/21. In the first package, we have 0.73 dollars per ounce.
Now, let's look at the second package. We start by multiplying 1.4*12=16.8. There are 16.8 ounces in the package. Now, we divide 15.35/16.8=0.91. So, in the second package, we have 0.91 dollars per ounce.
The cost per ounce of the 10-pack is $0.73 and the cost per ounce of the 12-pack is $0.91. The first package has the better price per ounce.
The better explanation is the second one, because I prefer the lower price per ounce, I think that the 1st pack is the better buy.
Square ABCD of the translation T-3,-8(x,y)
Applying Newton's Second Law, it is found that the force, in Newtons, is given by:
![F = 10[v(21) - v(16)]](https://tex.z-dn.net/?f=F%20%3D%2010%5Bv%2821%29%20-%20v%2816%29%5D)
Newton's Second Law states that Force, in Newtons, is <u>mass times acceleration</u>, that is:

In this problem, mass of 50 kg, thus 
Acceleration is <u>change in velocity divided by change in time</u>, that is:

In this problem, we don't know the velocities, but know that time is from 16s to 21s, thus:


Thus, the force is given by:


![F = 50\frac{[v(21) - v(16)]}{5}](https://tex.z-dn.net/?f=F%20%3D%2050%5Cfrac%7B%5Bv%2821%29%20-%20v%2816%29%5D%7D%7B5%7D)
![F = 10[v(21) - v(16)]](https://tex.z-dn.net/?f=F%20%3D%2010%5Bv%2821%29%20-%20v%2816%29%5D)
A similar problem is given at brainly.com/question/18801986