Answer:
X=-1/3 y-2
Step-by-step explanation:
Let's solve for x.
y
=
−
3
x
−
6
Step 1: Flip the equation.
−
3
x
−
6
=
y
Step 2: Add 6 to both sides.
−
3
x
−
6
+
6
=
y
+
6
−
3
x
=
y
+
6
Step 3: Divide both sides by -3.
−
3
x
−
3
=
y
+
6
−
3
x
=
−
1
3
y
−
2
Answer:
x
=
−
1
3
y
−
2
Your answer is 150 million kilometers
C = child tickets
a = adult tickets
Solve this with the substitution method.
Make two equations:
6.30c + 9.90a = 1,246.50
c + a = 159
Solve for c.
Subtract 9.90a from both sides.
6.30c = 1,246.50 - 9.90a
Divide both sides by 6.30.
c = 197.86 - <span>1.57a (rounded to hundredths)
Plug c into second equation.
</span>197.86 - 1.57a + a = 159
Combine like terms.
197.86 - 0.57a = 159
Subtract 197.86 from both sides.
-0.57a = -38.86
Divide both sides by -0.57.
a = <span>68.18
round up to ones: 68
</span>
![\boxed {68~adult~tickets}](https://tex.z-dn.net/?f=%5Cboxed%20%7B68~adult~tickets%7D)
were sold.<span>
</span>
We are given the function:
![g(x) = \frac{1}{x-6}](https://tex.z-dn.net/?f=%20g%28x%29%20%3D%20%5Cfrac%7B1%7D%7Bx-6%7D%20%20)
Domain:
The domain is the set of all possible x-values which will make the function "work", and will output real y-values.
In case of fractions, we must not have the denominator as zero , otherwise the function will become undefined.
So equating denominating equal to zero to find restriction.
![x-6=0](https://tex.z-dn.net/?f=%20x-6%3D0%20)
x=6
So at x=6 , the function becomes undefined.
So domain is all real numbers except x=6.
Range:
For a fraction, we find domain of inverse function and that gives the range.
![g(x) = \frac{1}{x-6}](https://tex.z-dn.net/?f=%20g%28x%29%20%3D%20%5Cfrac%7B1%7D%7Bx-6%7D%20%20)
replacing g(x) by y
![y = \frac{1}{x-6}](https://tex.z-dn.net/?f=%20y%20%3D%20%5Cfrac%7B1%7D%7Bx-6%7D%20%20)
switching y by x and x by y
![x = \frac{1}{y-6}](https://tex.z-dn.net/?f=%20x%20%3D%20%5Cfrac%7B1%7D%7By-6%7D%20%20)
solving for y,
![y=\frac{1}{x} +6](https://tex.z-dn.net/?f=%20y%3D%5Cfrac%7B1%7D%7Bx%7D%20%2B6%20)
Now here we find domain of this function.
Again for a fraction denominator cannot be zero
So range is :
g(x) >0 and g(x) <0