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3 years ago

9

Find the area of the figure.

2 answers:

Black_prince [1.1K]3 years ago

6 0

I actually don’t really know it

Nitella [24]3 years ago

6 0

132 inches squared. I did this in my head.

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If you have designed a test that measures principal leadership, and want to explore whether there are other constructs that are

DIA [1.3K]

Answer:

Factor analysis

Step-by-step explanation:

Factor Analysis is a method for modeling observed variables, and their covariance structure, in terms of a smaller number of underlying unobservable “factors.” These factors are typically viewed as broad concepts or ideas that may describe a noted occurrence.

Take for example:

A basic impulse of acquiring a certain social level might explain most consumption behavior. These unobserved factors are more interesting to the social scientist than the noted numerical measurements.

6 0

3 years ago

A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si

Grace [21]

Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

$Area = 128$

Let the dimension of the paper be x and y;

Such that:

$Length = x$

$Width = y$

So:

$Area = x * y$

Substitute 128 for Area

$128 = x * y$

Make x the subject

$x = \frac{128}{y}$

When 1 inch margin is at top and bottom

The length becomes:

$Length = x + 1 + 1$

$Length = x + 2$

When 2 inch margin is at both sides

The width becomes:

$Width = y + 2 + 2$

$Width = y + 4$

The New Area (A) is then calculated as:

$A = (x + 2) * (y + 4)$

Substitute $\frac{128}{y}$ for x

$A = (\frac{128}{y} + 2) * (y + 4)$

Open Brackets

$A = 128 + \frac{512}{y} + 2y + 8$

Collect Like Terms

$A = \frac{512}{y} + 2y + 8+128$

$A = \frac{512}{y} + 2y + 136$

$A= 512y^{-1} + 2y + 136$

To calculate the smallest possible value of y, we have to apply calculus.

Different A with respect to y

$A' = -512y^{-2} + 2$

Set

$A' = 0$

This gives:

$0 = -512y^{-2} + 2$

Collect Like Terms

$512y^{-2} = 2$

Multiply through by $y^2$

$y^2 * 512y^{-2} = 2 * y^2$

$512 = 2y^2$

Divide through by 2

$256=y^2$

Take square roots of both sides

$\sqrt{256=y^2$

$16=y$

$y = 16$

Recall that:

$x = \frac{128}{y}$

$x = \frac{128}{16}$

$x = 8$

Recall that the new dimensions are:

$Length = x + 2$

$Width = y + 4$

So:

$Length = 8 + 2$

$Length = 10$

$Width = 16 + 4$

$Width = 20$

To double-check;

Differentiate A'

$A' = -512y^{-2} + 2$

$A" = -2 * -512y^{-3}$

$A" = 1024y^{-3}$

$A" = \frac{1024}{y^3}$

The above value is:

$A" = \frac{1024}{y^3} > 0$

This means that the calculated values are at minimum.

<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>

3 0

3 years ago

Which of the following is the vertex of the equation \large x^2-2x=-5 ?

Lelu [443]

I think it’s C but I’m not too sure

8 0

3 years ago

Show me how to solve 6j-3 for j=4

aleksklad [387]

Answer:

21

Step-by-step explanation:

plug in 4 where you have the j

6(4)-3=

24-3=

21

6 0

3 years ago

Samantha plays a trivia game. She earns 3 points for each

Rudiy27

この質問は緒と面白いね

11x3=33

33-4x0.75=30

頑張ってね！

5 0

3 years ago