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Hunter-Best [27]
3 years ago
14

First year students in rolled at a college were asked whether they play video games. The responses, classified by whether the st

udents were enrolled in the school of sciences the school of arts are shown in the table.
Mathematics
1 answer:
Irina18 [472]3 years ago
3 0
Where’s the table lol
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A is plotted on a coordinate grid at start bracket negative 3 and 1 over 2, 2 end bracket.. Choose the correct grid that best sh
ra1l [238]

Answer:

B

Step-by-step explanation:

have a good day and stay safe

5 0
3 years ago
PLEASE HELP URGENT WILL MARK BRAINLIEST DO NOT WASTE ANSWERS
earnstyle [38]

Answer:

A

Step-by-step explanation:

it says it is currently at 60 watts, if its tripled (times 3) that meansits times 3 and 60 times 3 is 180 so its A therefore.

8 0
3 years ago
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Can somebody please walked through this, I'm so confused and I have a test in 6 hours...
erastova [34]

Answer:

Q3: x = 4, y = 4, z = 4

Q4: x = 6, y = 0, z = -4

Step-by-step explanation:

Question 3: Simultaneous equations requires us to solve for x, y and z.

Since all three equations have a z in them, I will first solve for z.

Substitute in the first and third equation into the second equation.

First equation: x = 5z - 16

Second Equation: -4x + 4y - 5z = -20

Third equation: y = -z + 8

Substituting in x = 5z - 16 and y = -z + 8 for the x and y in the second equation.

-4(5z - 16) + 4(-z + 8) - 5z = -20

Expand

-20z + 64   - 4z + 32   - 5z = -20

Simplify and solve for z by putting all the numbers on one side and all the z's on the other side of the equals

-20z - 4z - 5z = -20 - 32 - 64

-29z = -116

z = -116/-29

z = 4

Substitute in this z value into the first and last equation and then solve for x and y

x = 5z - 16

x = 5(4) - 16

x = 20 - 16

x = 4

And

y = -z + 8

y = -(4) + 8

y = 4 (Its just a coincidence that they all equal to 4, I promise)

Question 5: A little bit harder of a question. Since the first and second equation both only have y and z, we can solve it using the elimination method.

Rearrange them so that the letters are on one side and numbers on the other side.

First equation: y + 6z = -24

Second equation: z + 2y = -4

I will choose to eliminate the y (You can choose either or)

Multiply the first equation by 2

2(y + 6z = -24)

2y + 12z = -48

Now that 2y is in both equations, we can minus one equation from the other to eliminate the y (I will minus the second from the first)

First Eq: 2y + 12z = -48

Second Eq: z + 2y = -4

2y - 2y = 0y

12z - z = 11z

-48 - (-4) = -44

Type these answers into a new equation

0y + 11z = - 44

Since y is 0, ignore it. Solve for z

11z = -44

z = -44/11

z = - 4

Substitute our z into either the first or second equation and solve for y (It doesnt matter which one you choose, I just did the second equation)

z + 2y = -4

(-4) + 2y = -4

2y = -4 + 4

2y = 0

y = 0

Substitute in our y and z values into the third equation and solve for x

-6x - 6y - 6z = -12

-6x - 6(0) - 6(-4) = -12

-6x - 0 + 24 = -12

-6x = -12 - 24

-6x = -36

x = -36/-6

x = 6

6 0
3 years ago
Read 2 more answers
Use the distance formula to show algebraically and graphically that the following two circles do not intersect. (x-1)²+(y+2)²=1
lesya692 [45]

Answer and Step-by-step explanation:

C1) (x-1)²+(y+2)²=1  C1 (1,-2) R1 = √1 = 1

C2) (x+5)²+(y-4)²=4 C2 (-5,4) R2 = √4 = 2

DISTANCE FORMULA: d² = (y₂-y₁)²+(x₁-x₂)²

calculating the distances between the 2 center:

d² = (4-(-2))²+(-5-1)² = (6)²+(-6)² = 36 + 36 = 72 ⇒ d = √72

√72 ≈ 8.49

R1 = 1 and R2 = 2

If the circles were secants, d would be < than R1 + R2.

If the circles were tangent, d would be = to  R1 + R2

As d > than R1 + R2, we know that the circles do not intercept.

3 0
3 years ago
What is the constant term in the expression 6x^3y + 8x^2 + 5x + 7? (Input a numeric value only.) (3 points)
Zinaida [17]
The constant term is 7. this is because x and y are unknowns and change depending on the other. As 6x^3y will change depending on what x or y is so will: 8x^2 and 5x therefore 7 is the constant term.
7 0
3 years ago
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