Answer:
324
Explanation:
Calculation to determine What order quantity maximizes expected profit for Bakery A
First step is for the Salvage value
Salvage value = $2 × (1 - 80%)
Salvage value= $0.40
Second step is to calculate the Overage cost
Overage cost = $0.50 - $0.40
Overage cost = $0.10
Second step is to calculate the Underage cost
Underage cost = $2 - $0.50
Underage cost = $1.50
Third step is to calculate the The critical ratio
The critical ratio = 1.5/(1.5 + 0.4) = 0.79. z = 0.8
Now let calculate the Order quantity
Order quantity = 300 + (0.8× 30)
Order quantity= 324
Therefore the order quantity maximizes expected profit for Bakery A is 324
Are they’re multiple answers choices or a open question
Answer:
10 minutes
Explanation:
Data provided in the question
Reception taking time = 3 minutes
Car wash taking time = 5 minutes
Paying the cash register taking time = 4 minutes
Returning to car and leaving taking time = 2 minutes
So, the theoretical flow time in minutes is
= Reception taking time + maximum time of car wash and paying the cash register + returning to car and leaving taking time
= 3 minutes + 5 minutes + 2 minutes
= 10 minutes
The total fixed cost should equal $1000.
<h3>What is the total fixed cost?</h3>
The first step is to determine the average fixed cost. The average fixed cost can be determined by subtracting the average variable costs from average total costs.
$70 - $60 = $10
Total fixed cost is the product of average fixed cost and output
100 x $10 = $1000
To learn more about cost, please check: brainly.com/question/26502221
Answer:
Explanation:
Terminal or horizon date is a point in time where a company's dividend experiences a constant growth rate.
In this case, it is mentioned that non-constant growth rate of 20% will happen for first two years and thereafter, a constant rate of 5%; this means that
D1= 1.25(1.20) =1.5
D2 = 1.5 (1.20)= 1.8
Then starting at D3, there's a constant growth rate = 5% so,
D3 = 1.8 (1.05)= 1.89
D4 = 1.89(1.05)= 1.9845
D5 = 1.9845 (1.05) = 2.0837
.....and so on
Therefore, the horizon date would be at the end of the second year i.e. End of Year 2.