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hjlf
3 years ago
10

Find the value of each variable.​

Mathematics
1 answer:
insens350 [35]3 years ago
4 0

Step-by-step explanation:

11)

x= 5

{y}^{2}  = 2 \times  {5}^{2}  \\  {y}^{2}  = 50 \\ y = 5 \sqrt{2}

12)

\tan(30 )  =  \frac{9}{y}  \\ y =  \frac{9}{ \tan(30) }  = 9 \sqrt{3}  \\  {x}^{2}  =  {9}^{2}  +  {(9 \sqrt{3} )}^{2}  \\  {x}^{2}  = 324 \\ x = 18

13)

\sin(60)  =  \frac{x}{22}  \\ x = 11 \sqrt{3}  \\  \cos(60)  =  \frac{y}{22}  \\ y = 11

14)

{16}^{2}  =  {x}^{2}  +  {y}^{2}  \\ x = y \\  {16}^{2}  = 2 {x}^{2}  \\ x = 8 \sqrt{2}  \\ y = 8 \sqrt{2}

15)

\tan(30)  =  \frac{x}{42}  \\ x = 14 \sqrt{3}  \\   \cos(30)  = \frac{42}{y}  \\ y =  \frac{42}{ \cos(30) }  \\ y = 28 \sqrt{3}

16)

{(19 \sqrt{2}) }^{2}  =  {x}^{2}  +  {y}^{2}  \\ x = y \\ 722 = 2 {x}^{2}  \\  {x}^{2}  = 361 \\ x = 19 \\ y = 19

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Using the given functions, it is found that:

  • Lower total cost at Jump-n-Play: 40, 64.
  • Lower total cost at Bounce house: 28, 8, 30.
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<h3>What are the cost functions?</h3>

For n visits to Jump-n-play, the cost is:

J(n) = 189 + 3n.

For n visits to Bounce Word, the cost is:

B(n) = 125 + 5n.

Comparing them, we have that:

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Hence:

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  • Lower total cost at Bounce house: 28, 8, 30.
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More can be learned about functions at brainly.com/question/25537936

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What is the value of p in the linear equation ? −4 −2 2 4
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You know that it represents the the height of the ball (in meters) when it is a distance "x" meters away from Rowan.

Since it is a Quadratic function its graph is parabola.

So, the maximum point of the graph modeling the height of the ball is the Vertex of the parabola.

You can find the x-coordinate of the Vertex with this formula:

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In this case:

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Then, substituting values, you get:

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