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tatiyna
3 years ago
14

Use a math drawing to explain why LaTeX: \frac{4}{5}=\frac{4\:\times3}{5\:\times3}\:=\frac{12}{15}4 5 = 4 × 3 5 × 3 = 12 15 .

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
6 0

Answer:

....................

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Need help on this problem
Taya2010 [7]

Answer:

Step-by-step explanation:

2(x-2)^2=8(7+y)\\2(x-2)^2=56+8y \Rightarrow y={1\over{8}}[2(x-2)^2-56]={1\over{4}}(x-2)^2-7\\finally\\y={1\over{4}}(x-2)^2-7\\let ~change~x~and~y\\x={1\over{4}}(y-2)^2-7\\x+7={1\over{4}}(y-2)^2\\4(x+7)=(y-2)^2\\y-2=\pm\sqrt{4(x+7)}\\\\y=2\pm\sqrt{4x+28}

7 0
3 years ago
Help please hhjhhkkkki
swat32

Answer:

000

Step-by-step explanation:

000

4 0
3 years ago
Read 2 more answers
Use the numbers from 1 to 9 to fill in the blanks to get the smallest possible answer.
Sloan [31]

Answer: first blank: 1

second blank: 9

third blank: -7

fourth blank: 2

1x-9=-7

x=2

4 0
3 years ago
One 6 oz juice box has 90 calories. How many calories are there in 64 oz jug of the juice? Round to the nearest calorie.
Aleonysh [2.5K]

Answer:

960 calories for the 64 oz jug

Step-by-step explanation:

6 oz for 90 calories.

64 oz for ??? calories.

It's a ratio, 6:90

and            64:???

so  6 * 10 2/3 is 64.

so 90 * 10 2/3 is ???

960 is ???

5 0
3 years ago
Read 2 more answers
Which of the following statements is true for the logistic differential equation?
solong [7]

Answer:

All of the above

Step-by-step explanation:

dy/dt = y/3 (18 − y)

0 = y/3 (18 − y)

y = 0 or 18

d²y/dt² = y/3 (-dy/dt) + (1/3 dy/dt) (18 − y)

d²y/dt² = dy/dt (-y/3 + 6 − y/3)

d²y/dt² = dy/dt (6 − 2y/3)

d²y/dt² = y/3 (18 − y) (6 − 2y/3)

0 = y/3 (18 − y) (6 − 2y/3)

y = 0, 9, 18

y" = 0 at y = 9 and changes signs from + to -, so y' is a maximum at y = 9.

y' and y" = 0 at y = 0 and y = 18, so those are both asymptotes / limiting values.

8 0
3 years ago
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