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cluponka [151]
2 years ago
14

Pedro ordered a pizza. The pizza place charges $12 for a large pizza plus an additional $2.50 per topping. The total cost of Ped

ro's pizza was $22. Write and solve an equation to determine many toppings Pedro ordered.​
Mathematics
2 answers:
Masja [62]2 years ago
6 0

Answer:

4 toppings

Step-by-step explanation:

22-12=10

2.50*?=10

2.50*4=10

4 toppings

trasher [3.6K]2 years ago
3 0

Answer:

12+(2.50x)

12+(2.50*4)

12+(10)

22

Step-by-step explanation:

x stands for number of toppings

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Complete Question

Pennsylvania Refining Company is studying the relationship between the pump price of gasoline and the number of gallons sold. For a sample of 14 stations last Tuesday, the correlation was 0.65.At the 0.01 significance level Can the company conclude that the correlation is positive

Answer:

Yes the company conclude that the correlation is positive

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  14

    The correlation is  r =  0.65

     

The  null hypothesis is  H_o :  r <  0

The  alternative hypothesis is  H_1 :  r > 0

Generally the standard deviation is mathematically evaluated as

       Sr =  \sqrt{1- r}

       Sr =  \sqrt{1- 0.65}

       Sr = 0.616

The  degree of freedom for the one-tail test is

       df =  n- 2

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        df = 12

The standard error is evaluated as

        SE  =  \frac{0.616}{ \sqrt{12} }

        SE  =0.1779

The test statistics  is evaluated as

      t =  \frac{r }{SE}

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The p-value of of  t is obtained from the z table, the value is  

        p-value =  P(t <  3.654) =  0.00012909

Given that p-value  <  \alpha  then we reject the null hypothesis

           Hence the company can conclude that the correlation is positive

     

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Answer:

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Step-by-step explanation:

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The slope of this equation is the coefficient of the variable a. Since the slope is positive, it means the freezing point of water increases by 0.0001 degrees Fahrenheit when the altitude increases by 1 foot.

For example, when a=1000, the freezing point is:

T(1000)= 0.0001*1000+32 = 32.1°F

When a=1001, the freezing point is:

T(1001)= 0.0001*1001+32 = 32.1001°F

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