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Pie
3 years ago
11

Help i dont get this

Mathematics
1 answer:
Oxana [17]3 years ago
8 0

substitute the place of the X

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find three consecutive integers. such that 4 times of first integer is 18 more than the sum of the second and third integer
Juliette [100K]

Three consecutive numbers are x, x+1 and x+2.

Four times the first integer is 4x

The sum of the second and third is (x+1)+(x+2)=2x+3.

So, we have

4x = 2x+3+18\iff 4x=2x+21

Subtract 2x from both sides:

2x=21

Divide both sides by 2:

x=10.5

So, you can't have three consecutive integers such that four times the first is 18 more than the sum of the other two: the three numbers would be 10.5, 11.5, 12.5.

In fact, you have

4\cdot 10.5 = 42

and

11.5+12.5+18 = 24+18=42

8 0
3 years ago
Uploaded the question thnx for the help
mariarad [96]
Answer : d

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3 years ago
Substitution method x=-y <br> 8x+3y=40
Delvig [45]
The answer would be 16
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6 plus 6 jkkjuuu jj jii yo uu
Contact [7]

Answer:

12 :D

Step-by-step explanation:

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Joyce paid $230 for an item at the store that was 20% off the original price. What was the original price?
Svetradugi [14.3K]

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250

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