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pantera1 [17]
3 years ago
13

PLEASE HELP MEEE I DONT GET THISSSSS

Mathematics
1 answer:
KiRa [710]3 years ago
4 0

Answer:

Root is a fancy word for a zero.

Using the quadratic formula you will get

x = 1.2, -.25

B is the correct answer. (-1/4)

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D) 5

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Which statements are true about the rules of multiplication for signed numbers? Check all that apply.
Mekhanik [1.2K]

Answer:

i think that 1, 3 and 4 are correct !!

Step-by-step explanation:

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4 0
4 years ago
The product of two mixed numbers x and y is 10. If x= _ 2/3 and y=_ 3/4 ,<br> find x and y?
Akimi4 [234]

Answer:

  • x = 2 2/3
  • y = 3 3/4

Step-by-step explanation:

There may be other ways to do this. Here's the approach I took. Let the integer part of x be represented by "a", and the integer part of y be represented by "b". Now, we have ...

  (a +2/3)(b +3/4) = 10

Multiplying by 12, this becomes ...

  (3a +2)(4b +3) = 120

There are only 16 divisors of 120, so they can be easily enough checked one at a time.

  120 = 1·120 = 2·60 = 3·40 = 4·30 = 5·24 = 6·20 = 8·15 = 10·12

Of these divisors, the ones that are of the form 3a+2 are ...

  2, 5, 8, 20 . . . . a=0, 1, 2, 6

The ones that are of the form 4b+3 are ...

  3, 15 . . . . b = 0, 3

The factor pair that consists of a number on the first list and a number on the second list is ...

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corresponding to a=2 and b=3. So, the mixed numbers you want are ...

  x = 2 2/3

  y = 3 3/4

_____

<em>Check</em>

  (2 2/3)·(3 3/4) =2·3 +2·3/4 +2/3·3 +2/3·3/4 = 6 +6/4 +2 +2/4 = 8+8/4 = 10

6 0
3 years ago
For each of the following numbers, write 4 decimals that would round to this whole number when rounde to the nearest whole numbe
Natalka [10]
Round to the nearest whole number:

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b) 28 ⇒ 27.5 ; 27.9 ; 28.1 ; 28.4
c) 32 ⇒ 31.5 ; 31.9 ; 32.1 ; 32.4
d) 50 ⇒ 49.5 ; 49.9 ; 50.1 ; 50.4
e) 67 ⇒ 66.5 ; 66.9 ; 67.1 ; 67.4
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If the following number is within the range of 1 to 4 then round down.
<span>If the following number is within the range of 5 to 9 then round up.</span>
8 0
3 years ago
What's the flux of the vector field F(x,y,z) = (e^-y) i - (y) j + (x sinz) k across σ with outward orientation where σ is the po
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\displaystyle\iint_\sigma\mathbf F\cdot\mathrm dS
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\displaystyle\iint_\sigma\mathbf F\cdot(\mathbf r_u\times\mathbf r_v)\,\mathrm dA

Since you want to find flux in the outward direction, you need to make sure that the normal vector points that way. You have

\mathbf r_u=\dfrac\partial{\partial u}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=\mathbf k
\mathbf r_v=\dfrac\partial{\partial v}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=-2\sin v\,\mathbf i+\cos v\,\mathbf j

The cross product is

\mathbf r_u\times\mathbf r_v=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\0&0&1\\-2\sin v&\cos v&0\end{vmatrix}=-\cos v\,\mathbf i-2\sin v\,\mathbf j

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\displaystyle\iint_\sigma(e^{-\sin v}\,\mathbf i-\sin v\,\mathbf j+2\cos v\sin u\,\mathbf k)\cdot(\cos v\,\mathbf i+2\sin v\,\mathbf j)\,\mathrm dA
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\displaystyle5\int_0^0e^t\,\mathrm dt+5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv

where t=-\sin v in the first integral, and the half-angle identity is used in the second. The first integral vanishes, leaving you with

\displaystyle5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv=5\left(v-\dfrac12\sin2v\right)\bigg|_{v=0}^{v=2\pi}=10\pi
5 0
3 years ago
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