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3 years ago

By rounding to 1 significant figure, estimate 361.42 / 79.45

Mathematics

1 answer:

Likurg_2 [28]3 years ago

4 0

Answer: 5

Step-by-step explanation:

To solve this, we would have to divide 361.42 by 79.45. This will be:

= 361.42 / 79.45

= 4.549

We can see that 4.549, has 4 significant digits. By the time we round it off to 1 significant number, we would have 5.

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What is the domain of the function y=in(x+2) x<-2 x>-2 x<2 x> x<-2 x>-2 x<2 x>2

aev [14]

For this case we must find the domain of the following function:

$y = ln (x + 2)$

By definition, the domain of a function is given by all the values for which the function is defined.

In this case, the argument of the expression must be greater than 0 to be defined.

$x + 2> 0\\x> -2$

Thus, the domain of the function is given by all the values of x greater than -2.

Answer:

Domain: $x> -2$

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2 years ago

Please solve this for me thank you!

melamori03 [73]

Answer:

620.14

Step-by-step explanation:

Original Equation:

$\frac{4y}{1.025^4}+y-2y(1.05)^2=1500$

Calculate exponents

$\frac{4y}{1.103812890625}+y-2y(1.1025)=1500\\$

Simplify:

$3.6238025791990193084270042653997y + y - 2.205y = 1500$

Add like terms

$2.4188025791990193084270042653997y \approx 1500$

Divide both sides by 7.012

$y\approx 213.91$ $y\approx620.14$

6 0

2 years ago

Read 2 more answers

I really need help ASAP!

Semmy [17]

Answer:

Because they are parallel:

Angles 1,3,5 and 7=125

180-125=55

Angles 2,4, 6 and 8=55

Hope this helps!

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3 years ago

Sketch the graph of y+2=1/2(x-3)

valentina_108 [34]

Answer:

Step-by-step explanation:

y= 1/2x + −7/2

5 0

2 years ago

The figure below shows square ABCD inscribed on square PQRM on a coordinate plane. Which of the following expressions represents

vova2212 [387]

The hypotenuse of the triangle is given by:
$CB ^ 2 = RC ^ 2 + RB ^ 2
$
Substituting values:
$CB ^ 2 = 2 ^ 2 + 4 ^ 2
$
Clearing CB we have:
$CB = \sqrt{ 2 ^ 2 + 4 ^ 2} 

 CB = \sqrt{ 4 + 16} 

 CB = \sqrt{20} 

 CB = \sqrt{4*5} 

 CB = 2\sqrt{5} 



$
Then, the perimeter of the triangle is:
$P = RB + RC + CB
$
Substituting values:
$P = 4 + 2 + 2 \sqrt{5} 

 P = 6 + 2 \sqrt{5}$
Answer:
the perimeter of triangle BRC in units is:
D.6 + 2√5

7 0

2 years ago

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