$1,130.28
Formula is A = P (1 + [r/n])^(nt)
A= 879 (1+ [.018/4])^(4*14)
A= 879 (1.0045)^56
A= $1,130.28
A = future total amount
P = principle (amount initially deposited)
r = the annual interest rate (decimal)
n = times that interest is compounded per year (quarterly is 4 times per year)
t = number of years
The closest to the minimum number of consumers needed to obtain the estimate with the desired precision is (b) 271
Explanation:
When the prior estimate of population proportion is not given , then the formula to find the sample size is given by :-
where E = Margin of error.
z* = Critical z-value.
As per given , we have
E = 5%=0.05
Confidence level = 90%
The critical value of z at 90% is 1.645 (By z-table)
Put all values in the formula , we get
n=0.25(1.645/0.05)²
n=0.25(32.9)²
n=270.6025≈271
Thus, the minimum sample size needed = 271
Hence , the correct answer is 271 .
Answer:
Explanation:
Direct labor and factory overhead
Answer:
The answer is 30%
Explanation:
Solution
Given that:
Project A
Project A costs = $350
Cash flows =$250 and $250 (next 2 years)
Project B
Project B costs =$300
Cash flow = $300 and $100
Now what is the crossover rate for these projects.
Thus
Year Project A Project B A-B B-A
0 -350 -300 -50 50
1 250 300 -50 50
2 250 100 150 -150
IRR 27% 26% 30% 30%
So,
CF = CF1/(1+r)^1 + CF2/(1+r)^2
$-50 = $-50/(1+r)^1 + $150/(1+r)^2
r = 30%
CF = CF1/(1+r)^1 + CF2/(1+r)^2
$50 = $50/(1+r)^1 + $-150/(1+r)^2
r = 30%
Hence, the cross over rate for these project is 30%
Note:
IRR =Internal rate of return
CF =Cash flow
r = rate
