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svetoff [14.1K]
3 years ago
12

HELP I have been stuck on this problem for a bit now

Mathematics
2 answers:
DENIUS [597]3 years ago
5 0

Answer:

16

Step-by-step explanation:

72/2 = 36

Square root of 36 is 6; 6 x 2 = 12

square root of 4 is 2 and 2^2 equals 4.

12 +4 =16

Mark me brainliest please

IgorC [24]3 years ago
4 0

Answer:

16

Step-by-step explanation:

72/2=36

square root 36=6

6*2=12

root4 squared is 4

12+4=16

Hope that helps :)

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What are the excluded values of x for x+4/-3x2+12x+36
grin007 [14]

Answer:

x = - 2, x = 6

Step-by-step explanation:

The denominator of the rational expression cannot be zero as this would make the expression undefined.

Equating the denominator to zero and solving gives the values that x cannot be.

Solve

- 3x² + 12x + 36 = 0 ( divide through by - 3 )

x² - 4x - 12 = 0 ← in standard form

(x - 6)(x + 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 6 = 0 ⇒ x = 6

x + 2 = 0 ⇒ x = - 2

x = - 2 and x = 6 ← are the excluded values

5 0
3 years ago
I need help can someone help me pls
sattari [20]

Answer:

D: 25 miles

Step-by-step explanation:

Pythagorean Theorem:

a^{2} + b^2 = c^2

36^2 + b^2  =  39^2

1,296 + b^2  =  1,521

b^2  =  225

b  =  25

4 0
3 years ago
What is the equation of the line that passes through the points (-1, 3) and (1, 11)
lina2011 [118]

Answer: To find the slope of this line, you would use the fomula

y2 - y1/ x2 - x1

11 - 3 / 1 - (-1)=

8/2

4

The slope of your line would be 4

3 0
3 years ago
Which value of x does not satisfy the equation sin^2x + sin x = 0
zzz [600]

Answer:

x \neq 0 \pm \pi \cdot i, \forall i \in \mathbb{N}_{O} and x \neq \frac{3\pi}{2}\pm 2\pi \cdot j, \forall j \in \mathbb{N}_{O}.

Step-by-step explanation:

The equation can be simplified with the help of trigonometric identities:

\sin x \cdot (\sin x + 1) = 0

Which means that equation is equal to zero if any component of the product is zero. The solutions of the expression are:

a) \sin x

x = 0 \pm \pi\cdot i,\forall i \in \mathbb{N}_{O}

b) \sin x + 1

\sin x + 1 = 0

\sin x = -1

x = \frac{3\pi}{2} \pm 2\pi\cdot i,\forall i \in \mathbb{N}_{O}

Any value different of both subsets do not satisfy the equation described above.

8 0
4 years ago
Solve the inequality for x: -3(2x+5) < -45
balandron [24]

Answer:

x>5

Step-by-step explanation:

-3(2x+5)<-45

2x+5<-45/-3

2x+5<15

2x<15-5

2x<10

x<10/2

x<5

x>5

7 0
4 years ago
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