Answer:
y = (x - 3)² + 1
Step-by-step explanation:
the equation of a quadratic function in vertex form is
y = a(x - h)² + k
where (h, k ) are the coordinates of the vertex and a is a multiplier
here (h, k ) = (3, 1 ) , then
y = a(x - 3)² + 1
to find a substitute (1, 5 ) into the equatiuon
5 = a(1 - 3)² + 1 ( subtract 1 from both sides )
4 = a(- 2)² = 4a ( divide both sides by 4 )
1 = a
then equation of quadratic function is
y = (x - 3)² + 1
Answer:
part A: The x-intercept of the graph is the point where the function crosses the x-axis. for f(x)=2x2-5x+3 its (1,0)
part B= If the parabola opens up, the vertex represents the lowest point on the graph, or the minimum value of the quadratic function. If the parabola opens down, the vertex represents the highest point on the graph, or the maximum value. In either case, the vertex is a turning point on the graph.
(5/
4
,
−
1
/8
) is the vertex for f(x)=2x2-5x+3
Step-by-step explanation:
It’s -7 because -7^2= 49-35-9=5
An easy way to do this is to parameterize the directed line segment from B to A by the function
with 0 ≤ t ≤ 1.
The point P₂ splits up AB so that BP₂ = 3/8 AB and AP₂ = 5/8 AB. Then we reach the point P₂ when t = 3/8, so its coordinates are
Hello there!
the answer would be A
Hope this helps! :)
~Zain
