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Alekssandra [29.7K]
3 years ago
15

At a dock on the east coast, low tide occurs at 3 pm wi th a water depth of 5 ft. The depth at high tide is 83 ft. High tide occ

urs every 6 hours. Explain how to find the sinusoidal function that models the depth in terms of time, x.
Mathematics
1 answer:
FromTheMoon [43]3 years ago
6 0

Answer:

The sinusoidal function that model the depth in terms of time, 'x', is presented here as follows;

f(x) = 39·sin((π/3)·x - π) + 5

Step-by-step explanation:

A sinusoidal function is given by the general function as follows;

y = A·sin(B·x + C) + D

Where;

A = The amplitude = (y_{max} - y_{min})/2 = (The high tide - The low tide)/2 = (83 ft. - 5 ft.)/2 = 39 ft.

The period, T = 2·π/b = 6 hours

∴ B = 2·π/T = 2·π/6 = π/3

D = The vertical shift = The low tide = 5 ft.

The horizontal phase shift, 'C', is given as follows;

3 hrs = -C/B = -C/(π/(3 hr))

C = 3 hrs × -(π/(3 hr)) = -π

∴ C = -π

y = 39·sin((π/3)·x - π) + 5

The sinusoidal function that model the depth in terms of time, 'x', is therefore given as follows;

f(x) = 39·sin((π/3)·x - π) + 5

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So the right options are:

y=-\frac{2}{5}x-1

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Further explanation:

Given equation of line is:

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We have to convert it into point-slope form

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The co-efficient of x is the slope of the line

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As the required line is parallel to given line, it will also have same slope.

Let m1 be the slope of required line

Then the line will be:

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Putting the value of slope

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Putting (-5,1) in the equation to find the value of b

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Putting the values of slope and b in equation

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Multiplying the whole equation by 5 will give us:

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Another form of equation of line is Point-slope form

y-y_1=m(x-x_1)

Putting the values of slope and point in the equation, we get

y-1=-\frac{2}{5}(x+5)

So the right options are:

y=-\frac{2}{5}x-1

2x+5y = -5

y-1=-\frac{2}{5}(x+5)

Keywords: Point-Slope form, Parallel lines

Learn more about point slope form at:

  • brainly.com/question/4464845
  • brainly.com/question/4522984

#LearnwithBrainly

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